Assignment 1

course Mth 151

hope this is how you send things

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Your work has been received. Please scroll through the document to see any inserted notes (inserted at the appropriate place in the document, in boldface) and a note at the end. The note at the end of the file will confirm that the file has been reviewed; be sure to read that note. If there is no note at the end, notify the instructor through the Submit Work form, and include the date of the posting to your access page.

16:32:56

Note that there are 4 questions in this assignment.

`q001. Let A stand for the collection of all whole numbers which have at least one even digit (e.g., 237, 864, 6, 3972 are in the collection, while 397, 135, 1, 9937 are not). Let A ' stand for the collection of all whole numbers which are not in the collection A. Let B stand for the collection { 3, 8, 35, 89, 104, 357, 4321 }. What numbers do B and A have in common? What numbers do B and A' have in common?

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RESPONSE -->

B and A have 8, 104, 89, and 4321 in common. B and A' have 3, 35, and 357 in common.

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16:41:54

Of the numbers in B, 8, 89, 104, 4321 each have at least one even digit and so are common to both sets. 3 is odd, both of the digits in the number 35 are odd, as are all three digits in the number 357. Both of these numbers are therefore in A ' .

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RESPONSE -->

Yep, thats what I got.

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16:44:34

`q002. I have in a room 8 people with dark hair brown, 2 people with bright red hair, and 9 people with light brown or blonde hair. Nobody has more than one hair color. Is it possible that there are exactly 17 people in the room?

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RESPONSE -->

No, it is not possible. The 8 people with dark hair plus the 2 with red equal 10. The other 9 people have light brown hair or blonde hair, since both of these colors are new, and no one has more than one hair color, it is not possible for there to be exactly 17 people.

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16:46:24

`q003. I have in a room 6 people with dark hair and 10 people with blue eyes. There are only 14 people in the room. But 10 + 6 = 16, which is more than 14. How can this be?

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RESPONSE -->

ok.

2 of the people have dair hair and blue eyes.

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16:46:57

The key here is that there is nothing mutully exclusive about these categories-a person can have blue eyes as well as dark hair. So if there are 2 people in the room who have dark hair and blue eyes, which is certainly possible, then when we add 10 + 6 = 16 those two people would be counted twice, once among the 6 blue-eyed people and once among the 10 dark-haired people. So the 16 we get would be 2 too high. To get the correct number we would have to subtract the 2 people who were counted twice to get 16 - 2 = 14 people.

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RESPONSE -->

Ok, thats basically what I was saying.

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16:48:30

`q004. In a set of 100 child's blocks 60 blocks are cubical and 40 blocks are cylindrical. 30 of the blocks are red and 20 of the red blocks are cubical. How many of the cylindrical blocks are red?

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RESPONSE -->

10 of the cyndrical blocks are red. Since there are 30 red blocks and 20 of them are cubical, the other 10 have to be cyndrical.

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16:48:36

Of the 30 red blocks 20 are cubical, so the rest must be cylindrical. This leaves 10 red cylindrical blocks.

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Good job. You submitted the right thing.

Let me know if you have questions.

Assignment 1

course Mth 151

hope this is how you send things

.......................................................!!!!!!!!...................................

Your work has been received. Please scroll through the document to see any inserted notes (inserted at the appropriate place in the document, in boldface) and a note at the end. The note at the end of the file will confirm that the file has been reviewed; be sure to read that note. If there is no note at the end, notify the instructor through the Submit Work form, and include the date of the posting to your access page.

16:32:56

Note that there are 4 questions in this assignment.

`q001. Let A stand for the collection of all whole numbers which have at least one even digit (e.g., 237, 864, 6, 3972 are in the collection, while 397, 135, 1, 9937 are not). Let A ' stand for the collection of all whole numbers which are not in the collection A. Let B stand for the collection { 3, 8, 35, 89, 104, 357, 4321 }. What numbers do B and A have in common? What numbers do B and A' have in common?

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RESPONSE -->

B and A have 8, 104, 89, and 4321 in common. B and A' have 3, 35, and 357 in common.

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16:41:54

Of the numbers in B, 8, 89, 104, 4321 each have at least one even digit and so are common to both sets. 3 is odd, both of the digits in the number 35 are odd, as are all three digits in the number 357. Both of these numbers are therefore in A ' .

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RESPONSE -->

Yep, thats what I got.

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16:44:34

`q002. I have in a room 8 people with dark hair brown, 2 people with bright red hair, and 9 people with light brown or blonde hair. Nobody has more than one hair color. Is it possible that there are exactly 17 people in the room?

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RESPONSE -->

No, it is not possible. The 8 people with dark hair plus the 2 with red equal 10. The other 9 people have light brown hair or blonde hair, since both of these colors are new, and no one has more than one hair color, it is not possible for there to be exactly 17 people.

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16:46:24

`q003. I have in a room 6 people with dark hair and 10 people with blue eyes. There are only 14 people in the room. But 10 + 6 = 16, which is more than 14. How can this be?

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RESPONSE -->

ok.

2 of the people have dair hair and blue eyes.

.................................................

......!!!!!!!!...................................

16:46:57

The key here is that there is nothing mutully exclusive about these categories-a person can have blue eyes as well as dark hair. So if there are 2 people in the room who have dark hair and blue eyes, which is certainly possible, then when we add 10 + 6 = 16 those two people would be counted twice, once among the 6 blue-eyed people and once among the 10 dark-haired people. So the 16 we get would be 2 too high. To get the correct number we would have to subtract the 2 people who were counted twice to get 16 - 2 = 14 people.

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RESPONSE -->

Ok, thats basically what I was saying.

.................................................

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16:48:30

`q004. In a set of 100 child's blocks 60 blocks are cubical and 40 blocks are cylindrical. 30 of the blocks are red and 20 of the red blocks are cubical. How many of the cylindrical blocks are red?

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RESPONSE -->

10 of the cyndrical blocks are red. Since there are 30 red blocks and 20 of them are cubical, the other 10 have to be cyndrical.

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16:48:36

Of the 30 red blocks 20 are cubical, so the rest must be cylindrical. This leaves 10 red cylindrical blocks.

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Good job. You submitted the right thing.

Let me know if you have questions.