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Phy 121
Your 'cq_1_07.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_07.1_labelMessages **
A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
• Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
First I found the final velocity by using the equation
‘ds = vAve * ‘dt
2m = vAve * .64
3.125 = vAve
vAve = (v0+vf)/2 and v0 = 0
3.125 * 2 = vf
6.25 m/s = vf
Now to find acceleration,
vf^2 = v0^2 + 2a’ds
(6.25)^2 = 2a * 2
39.06 = 4a
a = 9.77 m /sec^2
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• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
My acceleration value was not as close to 9.77m/sec^2. However, it was still relatively close at 9.07 m /sec^2. I did this the same way I did the first problem.
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• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
My answers were relatively close to this accepted value.
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&#This looks very good. Let me know if you have any questions. &#