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Phy 121
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_11.1_labelMessages **
Answer the following based on Newton's Second Law:
• How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
F = m * a
F = 12 kg * 3 m/s^2
F = 36 N
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• What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> :
F = m * a
A = Fnet / m
A = 20 N / 4kg
A = 5 m/s^2
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• If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> :
a = Fnet / m
a = 20N / 10kg
a = 2 m/s^2
I know there are other forces acting on the object besides my own because the calculations show that the object should be moving at an acceleration of 2 m/s^2. Since it is only moving at 1.5 m/s^2, then there is an opposing force acting upon the object.
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• What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> :
If I am pushing with a force of 20 N and the acceleration of the object is 1.5 m/s^s, then we can figure out that the opposing force is -5 N because:
20 + (-5N) = 15 N
Fnet = 15N
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15 min