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Phy 121
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_12.1_labelMessages **
Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
Force1 = 6kg*9.8 = 58.8 N
Force2 = 5kg*9.8 = 49 N
Fnet = F1 - F2 = 58.8 - 49 = 9.8 N
The net force is 9.8 N. Using the net force, we can find the system's acceleration.
Fnet = mass*acceleration
9.8 = 11*a
a = 0.89 m/s^2
The system is accelerating downward in the direction on the side with 6kg.
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• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
v0 = 1.8m/s
m = 11kg
a = -0.89m/s^2
vf= ?
t = 1
vf = v0 + at
vf = 1.8 + -0.89*1
vf = 0.91 m/s
If the side of the 5kg mass is positive, and the side of the 6kg mass is negative, then the 5kg mass will be traveling at a positive 0.91 m/s downward.
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• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
During the first second, the velocity and acceleration of the system are in opposite directions. Because of its initial velocity, the system is moving downward with the 5kg mass. However, the acceleration is upward towards the 6kg side at 0.89 m/s^2. Therefore, the system is slowing down.
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&#This looks very good. Let me know if you have any questions. &#