#$&*
Phy 121
Your 'cq_1_21.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
A ball is tossed vertically upward and caught at the position from which it was released.
• Ignoring air resistance will the ball at the instant it reaches its original position be traveling faster, slower, or at the same speed as it was when released?
answer/question/discussion: ->->->->->->->->->->->-> :
Ignoring air resistance, the ball at the instant it reaches its original position will be traveling the same speed as it took off with. Gravity has the same distance to both work against and then with the ball. There are no other net forces or resistances affecting the ball, so the speed at which the ball left the hand will be the same speed at which it returns to that exact position.
#$&*
• What, if anything, is different in your answer if air resistance is present? Give your best explanation.
answer/question/discussion: ->->->->->->->->->->->-> :
If air resistance is thrown into the equation, the ball should return to the original position at a slower speed than it took off. The air resistance works as friction to the force as the ball descends, making the velocity less. However, I don't think the air resistance effects the ball as it ascends.
#$&*
@&
As long as the ball is moving through the air, it experiences air resistance.
Since its initial upward speed is the greatest speed achieved during the entire trip up and down, in fact, the initial air resistance is the greatest.
*@
&#Good responses. See my notes and let me know if you have questions. &#