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course phy121
What are the average acceleration and final velocity of an object which accelerates uniformly from rest, attaining a velocity of 40 cm/sec in 13.6 seconds? How far does the object travel during the 13.6 seconds?We are asked to find: average acceleration, final velocity, and `ds.
We know:
v0=0cm/sec
vf= 40cm/sec
`dv = 40cm/sec
`dt = 13.6 seconds
Solutions
Average velocity = (v0+vf)/2 = (40cm/sec)/2 = 20 cm/sec.
Final velocity = 40 cm/sec
Avg velocity = `ds/`dt
20cm/sec = `ds/13.6 seconds
20cm/sec * (13.6 seconds) = `ds
`ds = 272 cm
Rate of change of position relative to clock time = `ds/`dt
Rate of change of position relative to clock time = 272 cm / 13.6 seconds = 20 cm per second
average acceleration = ‘dv/’dt = (40cm/sec)/13.6 seconds = 2.94 cm/sec^2
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