#$&* *#&!*#&!*#&!*#&! The average rate of change of the balls position with respect to clock time is (20cm-10cm)/(9s-4s)= 2cm/s/ If the position of a ball rolling along a track changes from 10 cm to 20 cm while the clock time changes from 4 seconds to 9 seconds, what is the average rate of change of its position with respect to clock time during this interval? The averabe rate of change is ((40cm/s / 10cm/s)/ 3s= 10cm. /If the velocity of a ball rolling along a track changes from 10 cm / second to 40 cm / second during an interval during which the clock time changes by 3 seconds, then what is the average rate of change of its velocity with respect to clock time during this interval? The average rate at which position changes is (5cm/s)/10s= 0.5cm /If the average rate at which position changes with respect to clock time is 5 cm / second, and if the clock time changes by 10 seconds, by how much does the position change? Average rate=(change in A) / (change in B) is what I need to remember./ You will be expected hereafter to know and apply, in a variety of contexts, the definition given in this question. You need to know this definition word for word. If you try to apply the definition without using all the words it is going to cost you time and it will very likely diminish your performance. Briefly explain how you will ensure that you remember this definition. / From what I remember from calculus derivative means rate of change. This seems to be the same thing except its average rate of change, but I think basically it is the same thing. Basically the procedure is to divide A by B. First you must know A and B. Sometimes this is given, and somtimes it must be deduced, often by subtraction./You are asked in this exercise to apply the definition, and given a general procedure for doing so. Briefly outline the procedure for applying this definition, and briefly explain how you will remember to apply this procedure.