course Mth 151 I am having a difficult time understanding the circuits. Any insights to the last problem would be greatly appreciated. ý›Ä…»Ÿ†o¼yÜr»áü}ôØ”ÝxÐÔö}üassignment #014
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00:57:01 3.3.6 rewrite using if then ' all marines love boot camp '.
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RESPONSE --> If you are a marine, then you love boot camp. confidence assessment: 3
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00:58:52 ** The statement is equivalent to 'If it's a Marine, it loves boot camp' or equivalent. The statement is not equivalent to 'if it is boot camp, then all Marines love it', which is the converse of the original statement. **
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RESPONSE --> I wrote ""If you are a marine, then you love boot camp."" I understand the statement that it is not equivalent to but is my statement correct or should I have wrote it just like yours? self critique assessment: 2
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01:00:23 3.3.18 ~p false q false p -> q true
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RESPONSE --> This statement would be false because ~p is false so p is true and p->q would be false. confidence assessment: 3
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01:00:39 ** Since ~p is false then p is true. Since q is false it follows that p -> q is of the form T -> F, which is false. The conditional is false when, and only when, the antecedent is true and the consequent false. **
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RESPONSE --> I understand this. self critique assessment: 3
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01:01:21 Query 3.3.36 write in symbols 'If play canceled, then it does not rain.'
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RESPONSE --> p->~r confidence assessment: 3
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01:01:35 ** If p stands for 'play canceled' and r for 'it rains' then the statement would be p -> ~q. **
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RESPONSE --> I understand this. self critique assessment: 3
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01:04:11 Query 3.3.48 q true, p and r false, evaluate and (-r U p) -> p
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RESPONSE --> ~r would be true and p would be false so (~rVp) would be True and p is false so (~rVp)->p is false. confidence assessment: 3
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01:04:38 ** The antecedent (~r U p ) would be true, since ~r true and p false. The consequent p would be false. Since the antecedent is true and the consequent false, the conditional is false. **
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RESPONSE --> I understand this. self critique assessment: 3
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01:07:48 Query 3.3.60 truth table for (p ^ q) -> (p U q)
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RESPONSE --> p q (p^q) (pVq) (p^q)->(pVq) T T T T T T F F T T F T F T T F F F F F confidence assessment: 2
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01:09:06 ** The headings would be p, q ,(p^q), (pUq), (p^q)->(pUq) Row 1 would read T T T T T Row 2 would read T F F T T Row 3 would read F T F T T Row 4 would read F F F F T The common sense of this is that whenever both p and q are true, then the statement 'p or q' must be true. That's what means to say (p ^ q) -> (p U q). The fact that this statement is true is indicated by the last column of the truth table, which has True in every possible case. **
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RESPONSE --> I slightly messed up on this one. I think it was in the last column but I do understand and think I just messed up on one of the disjunctions. self critique assessment: 2
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01:10:22 Query 3.3.72 negation of ' if loving is wrong then I don't want to be right'
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RESPONSE --> Loving you is wrong and I don't want to be right. confidence assessment: 2
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01:11:27 ** The negation has to have the exact opposite truth values of the original statement. It is difficult and confusing to try to negate a conditional. It is much easier to translate the conditional to a disjunction then negate the disjunction. It is easy to negate the disjunction using deMorgan's Laws. Since p -> q is identical to ~p U q, the negation of p -> q is ~ ( ~p U q), which by de Morgan's Law is ~ ~p ^ ~q, or just p ^ ~q. So the negation would ge 'loving you is wrong AND I want to be right. COMMON ERROR AND NOTE: If loving you is wrong, then I want to be right. INSTRUCTOR COMMENT: The negation of a conditional can't be a conditional (a conditional is false in only one case so its negation would have to be false in three cases). **
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RESPONSE --> I wrote ""Loving you is wrong and I don't want to be right. I should have said ""I want to be right. I just got in a hurry. self critique assessment: 2
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01:13:56 Query 3.3.90 circuit q parallel [ p in series with ( q par. ~p) ].
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RESPONSE --> I honestly don't know were to start with these problems. I read the section in the book but am still confused. confidence assessment: 0
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01:17:20 ** If I'm looking at the same circuit you are the translation would be q U [ p ^ [q U ~p ]] . Since intersection and union each distribute over the other, this would simplify to q U [ ( p ^ q) U ( p ^ ~p) ]. Since p ^ ~p can't be true, this is the same as q U ( p ^ q). Since q U ( p ^ q) is true whenever q is true and false whenever q is false expression is true exactly when q is. So the circuit finally simplifies to just q. You should be able to see by looking at the circuit that current will flow whenever all the q switches are closed. **
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RESPONSE --> I don't understand this at all. It is so foreign to me that I don't even know what questions to ask to help understand it. I'll keep reading the text over to try to get it. self critique assessment: 1
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