course Phy 121
A bee is making a beeline for its hive. Its velocity is measured at a distance of 75 meters from the observer and again at distance 145 meters from the observer. The clock times at these two positions are t = 9 sec and t = 16 sec, and the measured velocities are 3 m/sec and 13.5 m/sec. What is its average velocity during this time? What is its average acceleration during this time? Is it possible that the acceleration is uniform? Average velocity--
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vAve = 'ds/'dt
vAve = 145 m - 75 m/ 16 sec - 9 sec
vAve = 70 m/7 sec
vAve = the bee's average velocity was 10 m/s
Average acceleration--
aAve = 'dv/'dt
aAve = 13.5 m/sec - 3 m/sec ÷ 16 sec - 9 sec
aAve = 10.5 m/sec ÷ 7 sec
aAve = 1.5 m/s^2
I don't believe that the acceleration of our bee is uniform. It's final velocity was over twice that of its initial velocity"
Good work, except for the part about uniform acceleration. You're on the right track there too, but final velocity is equal to double ave velocity only in the case where initial velocity is zero.
In all cases, though, if acceleration is uniform then the average velocity (which you calculated correctly from its definition) is equal to the average of the initial and final velocities.
What is the average of the initial and final velocities and how does that compare with the average velocity you found? What therefore is your conclusion?