cq_1_081

#$&*

Phy 231

Your 'cq_1_08.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** **

A ball is tossed upward with an initial velocity of 25 meters /

second. Assume that the acceleration of gravity is 10 m/s^2

downward.

What will be the velocity of the ball after one second?

answer/question/discussion: ->->->->->->->->->->->-> :

vf = v0 + a * t

vf = 25 - 10 * 1

vf = 15 m/s

#$&*

What will be its velocity at the end of two seconds?

answer/question/discussion: ->->->->->->->->->->->-> :

vf = v0 + a * t

vf = 25 - 10 * 2

vf = 5 m/s

#$&*

During the first two seconds, what therefore is its average

velocity?

answer/question/discussion: ->->->->->->->->->->->-> :

(25+5) / 2

= 15 m/s

#$&*

How far does it therefore rise in the first two seconds?

answer/question/discussion: ->->->->->->->->->->->-> :

ds = v0 * t + 0.5 * a *t^2

ds = 25 * 2 + 0.5 * -10 * 2^2

ds = 30 m

#$&*

What will be its velocity at the end of a additional second, and

at the end of one more additional second?

answer/question/discussion: ->->->->->->->->->->->-> :

vf = v0 + a * t

vf = 25 -10 * 3

vf = -5 m/s

vf = v0 + a * t^2

vf = 25 - 10 * 4^2

vf = -15 m/s

#$&*

At what instant does the ball reach its maximum height, and how

high has it risen by that instant?

answer/question/discussion: ->->->->->->->->->->->-> :

vf = v0 + a * t

0 = 25 -10 * t

t= 2.5 s

ds = v0 * t + 0.5 * a * t^2

ds = 25 * 2.5 + 0.5 * -10 * 2.5^2

ds = 31.25

#$&*

What is its average velocity for the first four seconds, and how

high is it at the end of the fourth second?

answer/question/discussion: ->->->->->->->->->->->-> :

(25-15)/2

= 5 m/s

#$&*

How high will it be at the end of the sixth second?

answer/question/discussion: ->->->->->->->->->->->-> :

ds = v0 * t + 0.5 * a * t^2

ds = 25 * 6 + 0.5 * -10 * 6^2

ds = -30 m

#$&*

*#&!

&#Very good responses. Let me know if you have questions. &#