#$&*
Phy 231
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Masses of 5 kg and 6 kg are suspended from opposite sides of a
light frictionless pulley and are released.
What will be the net force on the 2-mass system and what will be
the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
side 1
Fnet = m * a
Fnet = 5 * 9.8
Fnet = 49 N
side 2
Fnet = m * a
Fnet = 6 * 9.8
Fnet = 58.8 N
system
Fnet = 58.8 - 49
Fnet = 9.8 N
Accel of sys
Fnet = m * a
9.8 = 11 * a
a = 0.89 m/s^2 downward for side 2 and upward for side 1
#$&*
If you give the system a push so that at the instant of release
the 5 kg object is descending at 1.8 meters / second, what will
be the speed and direction of motion of the 5 kg mass 1 second
later?
answer/question/discussion: ->->->->->->->->->->->-> :
t = 0
V0 = vf = 1.8 m/s
t = 1
vf = v0 + a * t
vf = 1.8 + 9.8 * 1
@& The system doesn't accelerate at 9.8 m/s^2. You found the acceleration previously.*@
vf = 11.6 m/s
a = 11.6/1 = 11.6 m/s^2
Fnet = m * a
Fnet = 5 * 11.6 58 N downward
#$&*
During the first second, are the velocity and acceleration of the
system in the same direction or in opposite directions, and does
the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
They are in the same direction and they do slow down do to the
negative acceleration on the other side.
#$&*
*#&!
@&
&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your old and new solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#
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