ASSIGNMENT 9 QUERY

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20:02:09 Symbolic calculation of slope, preliminary exercise What was the function, between which two points were you to calculate the average slope and how did you get this slope?

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RESPONSE --> the function was linear. the points at which i calculated the average slope were (-2,-2.6) and (7,16.6) the slope was gotten by x2-x1 divided by y2-y1.

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20:06:34 ** For the function y = .1 x^2 - 3 between x = -2 and x = 7 we get: slope = (y2 - y1) / (x2 - x1). For x1 = 2 and x2 = 7 we have y2 = .1 * 7^2 - 3 = 1.9 and y1 = .1 * 2^2 - 3 = -2.6, so slope = (1.9 - (-2.6) ) / ( 7 - 2) = 4.5 / 5 = .9. **

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20:25:25 problem 2 symbolic expression for slope, fn depth(t). What is the expression for the slope between the two specified t values?

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RESPONSE --> (10,f(10)) (30,f(30)) so f(30)-f(10)/30-10

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20:25:51 ** The function is given a name: depth(t). t values are 10 and 30. So rise = depth(30) - depth(10) and run = 30 - 10 = 20. Thus slope = [ depth(30) - depth(10) ] / 20 . **

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20:26:13 What is the rise between the two specified t values?

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RESPONSE --> f(30)-f(10)

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20:26:21 ** The rise is the change in depth. The two depths are depth(10) and depth(30). The change in depth is final depth - initial depth, which gives us the expression depth(30)-depth(10) **

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20:26:26 What is the run between the two specified t values?

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RESPONSE --> 20

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20:26:29 ** run = 30 - 10 = 20 **

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20:26:56 What therefore is the slope and what does it mean?

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RESPONSE --> F(30)-F(10) 20 IT MEANS WE NEED TO SOLVE FOR THE FUNCTION OF THE DEPTH

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20:27:05 ** rise = depth(30)-(depth(10) indicates change in depth. run = 30 - 10 = 20 = change in clock time. Slope = rise / run = (depth(30) - depth(10) ) / 20, which is the average rate at which depth changes with respect to clock time between t = 10 and t = 30. **

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20:49:28 problem 5 graph points corresponding to load1 and load2 What are the coordinates of the requested graph points?

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RESPONSE --> (LOAD,F(LOAD1)) (LOAD,F(LOAD2))

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20:51:08 ** The horizontal axis is the 'load' asix, the vertical axis is the springLength axis. The load axis coordinates are load1 and load2. The corresponding spring lengths are springLength(load1) and springLength(load2). The springLength axis coordinates are springLength(load1) and springLength(load2). The graph points are thereofore (load1, springLength(load1) ) and (load2, springLength(load2) ). **

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20:51:41 What is your expression for the average slope of the graph between load1 and load2?

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RESPONSE --> L2-L1 LOAD2-LOAD1

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20:51:49 ** rise = springLength(load2) - springLength(load1) run = load2 - load1 so slope = [ springLength(load2) - springLength(load1)] / (load2 - load1). **

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21:14:32 problem 6 symbolic expression for slope of depth function

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RESPONSE --> F(T2)-F(T1)RISE T2-T1 RUN

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21:14:36 ** the name of the function is depth(t). We need the slope between t = t1 and t = t2. The depths are depth(t1) and depth(t2). Thus rise is depth(t2) - depth(t1) and run is t2 - t1. Slope is [ depth(t2) - depth(t1) ] / (t2 - t1). **

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21:32:02 problem 8 average rate from formula f(t) = 40 (2^(-.3 t) ) + 25 intervals of partition (10,20,30,40) What average rate do you get from the formula? Show your steps.

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RESPONSE --> I HAVE NO CLUE

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21:34:37 ** ave rate = change in depth / change in t. For the three intervals we get (f(20)-f(10))/(20-10) = (25.625 - 30 )/(20 - 10) = -4.375 / 10 = -.4375 (f(30)-f(20))/(30-20) = (25.07813 - 25.625)/(30 - 20) = -.5469 / 10 = -.05469. (f(40)-f(30))/(40-30) = (25.00977 - 25.07813)/(40 - 30) = -.0684 / 10 = -.00684. **

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21:35:01 Add comments on any surprises or insights you experienced as a result of this assignment.

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RESPONSE --> I ACTUALLY UNDERSTOOD...THIS REALLY SUPRISED ME AND I FOUND IT KIND OF FUN.

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21:35:38 STUDENT RESPONSE: Ummm I know the slope formula is (y2-y1)/(x2-x1), but I always just put the number into the expression in the order I see them, but that is ok because I keep the order and get the correct answere because the y2,y1,x2,x1 or all relative. I am correct in doing this? INSTRUCTOR COMMENT: In other words you use (y1 - y2) / (x1 - x2) instead of (y2 - y1) / (x2 - x1). It's more conventional to regard, say, 10 as x1 and 20 as x2, so f(20) is y2 and f(10) is y1. If you start from the lower x number and change to the higher the difference is higher - lower, and this is the way we usually think about changes. According to this convention we calculate change in y as y2 - y1 and change in x as x2 - x1. You are doing (y1 - y2) / (x1 - x2) and you get a negative change in x, a negative denominator, and if you are thinking about change from the first quantity to the second this is backwards. However as you say both numerator and denominator follow the same order so you still get the right answer, since (y1-y2)/(x1-x2)= (y2-y1) / (x2-x1). **

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You did a good job here, though there were one or two places where a self-critique would have been a good idea. Let me know if you have questions.