course mth 163 can i shcedule a time to get help on a few things from you before the test i am a little confused, please let me know thru email.thank you
.................................................
......!!!!!!!!...................................
18:14:35 `q001. Note that this assignment has 3 questions If we know that y = k x^2, then if (x2/x1) = 7, what is (y2/y1)?
......!!!!!!!!...................................
RESPONSE --> y=14k
.................................................
......!!!!!!!!...................................
18:19:48 If y2 = k x2^2 and y1 = k x1^2, then y2 / y1 = (k x2^2) / ( k x1^2). Since k / k = 1 this is the same as y2 / y1 = x2^2 / x1^2, which is the same as y2 / y1 = (x2 / x1)^2. In words this tells us if y to is proportional to the square of x, then the ratio of y2 to y1 is the same as the square of the ratio of x2 to x1. Now if (x2 / x1) = 7, we see that y2 / y1 = (x2 / x1)^2 = 7^2 = 49.
......!!!!!!!!...................................
RESPONSE --> i had a clerical error with the square, instead of 7^2 i put 7*2=14. Luckily i caught myself on that one.
.................................................
......!!!!!!!!...................................
18:21:03 `q002. If we know that y = k x^3, then if (x2/x1) = 7, what is (y2/y1)?
......!!!!!!!!...................................
RESPONSE --> (yz/y2)=343
.................................................
......!!!!!!!!...................................
18:21:31 If y2 = k x2^3 and y1 = k x1^3, then y2 / y1 = (k x2^3) / ( k x1^3). Since k / k = 1 this is the same as y2 / y1 = x2^3 / x1^3, which is the same as y2 / y1 = (x2 / x1)^3. In words this tells us if y to is proportional to the cube of x, then the ratio of y2 to y1 is the same as the cube of the ratio of x2 to x1. Now if (x2 / x1) = 7, we see that y2 / y1 = (x2 / x1)^3 = 7^3 = 343.
......!!!!!!!!...................................
RESPONSE --> i was correct in the math on this one
.................................................
......!!!!!!!!...................................
18:22:52 `q003. If we know that y = k x^-2, then if (x2/x1) = 64, what is (y2/y1)?
......!!!!!!!!...................................
RESPONSE --> (y1/y2) would equal 4096
.................................................
......!!!!!!!!...................................
18:26:28 If y2 = k x2^-2 and y1 = k x1^-2, then y2 / y1 = (k x2^-2) / ( k x1^-2). Since k / k = 1 this is the same as y2 / y1 = x2^-2 / x1^-2, which is the same as y2 / y1 = (x2 / x1)^-2, which is the same as 1 / (x2 / x1)^2, which gives us (x1 / x2)^2. So if y = k x^-2, then (y2 / y1) = (x1 / x2)^2.( In words this tells us if y to is inversely proportional to the square of x, then the ratio of y2 to y1 is the same as the square of the ratio of x1 to x2 (note that this is a reciprocal ratio). Now if (x2 / x1) = 64, we see that y2 / y1 = (x1 / x2)^2 = (1/64)^2 = 1/ 4096.
......!!!!!!!!...................................
RESPONSE --> i am a little confused on this one as to how it is the same almost as the other problems and the correct answer was a fraction. i am having a real problem with the language that is used in these examples. is there somewhere i could go to see a problem that i could relate these to. I am getting really confused i need simple explanations.
.................................................