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Phy 201
Your 'cq_1_02.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_02.1_labelMessages.txt **
The problem:
A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.
· What is your best guess about the ball's average velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
I would guess that you could find the balls average velocity by doing 4 cm/sec + 10 cm/sec = 14 cm/sec then do 14 cm/s / 2 = 7 cm/s. I would guess that the balls average velocity would be 7 cm/s
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· Without further information, why is this just a guess?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
This is just a guess because I am unsure how we are suppose to come up with the average velocity. This is just what I think I might be able to do to come up with the answer. There is probably an equation that we need to use to find the answer.
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· If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during that time?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
I would guess that you would take the velocity that it is currently traveling and multiple it by 3 since it is traveling about that speed for about 3 seconds. It would have been picking up a little speed though since after 3 seconds it is at the second velocity so the answer we got above would have been a little short.
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Can you make a specific 'best guess'?
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· At what average rate did its velocity change with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The average rate of change of A with respect to B on an interval is: Average rate of change of A with respect to B = (change in A) / (change in B)
so Average rate of change of velocity with respect to seconds = change in velocity / 3 seconds
Since we don’t know the what the first and second velocity is then it would be hard to come up with a definite answer. Lets just say there was a difference of 1 cm/s in velocity since it says it starts at one velocity and makes it to the second velocity in 3 seconds. So:
Average rate of change of velocity with respect to seconds = 1 cm/sec / 3 sec = .33 cm/sec^2
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The ball accelerates from 4 cm/s to 10 cm/s.
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About 20 Minutes
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Your 7 cm/s 'best guess' is what would be expected.
You can be more specific in your other answers, and relate them to the given information.
&#Please see my notes and submit a copy of this document with revisions, comments and/or questions, and mark your insertions with &&&& (please mark each insertion at the beginning and at the end).
Be sure to include the entire document, including my notes. &#
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