Phy 201
Your 'cq_1_02.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds. The graph consists of a straight line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
• What is the clock time at the midpoint of this interval?
answer/question/discussion: 9 sec
• What is the velocity at the midpoint of this interval?
answer/question/discussion: 28 cm/s
• How far do you think the object travels during this interval?
answer/question/discussion: 212 cm
• By how much does the clock time change during this interval?
answer/question/discussion: 8 sec
• By how much does velocity change during this interval?
answer/question/discussion: 24 cm/s
• What is the average rate of change of velocity with respect to clock time on this interval?
answer/question/discussion: 3 cm/s
• What is the rise of the graph between these points?
answer/question/discussion: 3
• What is the run of the graph between these points?
answer/question/discussion: 1
• What is the slope of the graph between these points?
answer/question/discussion: 3
• What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion: The increase is constant
• What is the average rate of change of the object's velocity with respect to clock time during this interval?
answer/question/discussion: 3 cm/s
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20 min
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Your answers appear to be mostly correct. This can be an accident so it is clear that you are calculating these results correctly.
However you need to show a bit more of your calculations, and you need to include units at every step. Some of your answers don't contain units, and some contain units but the units are not correct and have not been related to the calculations.
Please see my notes and submit a copy of this document with revisions and/or questions, and mark your insertions with &&&&.