course phy201
6/24 11
Reason out the quantities v0, vf, Dv, vAve, a, Ds and Dt: If an object’s velocity changes at a uniform rate from 11 cm/s to 15 cm/s as it travels 130 cm, then what is the average acceleration of the object?Using the equations which govern uniformly accelerated motion determine vf, v0, a, Ds and Dt for an object which accelerates through a distance of 130 cm, starting from velocity 11 cm/s and accelerating at .4 cm/s/s.
v0 = 11cm/s
vf= 15cm/s
Dv=4cm/s
vAve=13 cm/s
a=.4cm/s^2
Ds=130 cm
Dt= 10s"
You still need to Use the equations which govern uniformly accelerated motion determine vf, v0, a, Ds and Dt for an object which accelerates through a distance of 130 cm, starting from velocity 11 cm/s and accelerating at .4 cm/s/s.
You know the solutions from the first question, but you can't use your foreknowledge of the answers. You have to use the equations of motion and show how you have done so.
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