phy201
Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
0th. At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
the acceleration is quicker when the car rolls down a steeper slope.
VAve= 10m/ 8s= 1.25m/s
Vf= 1.25m/s *2= 2.5m/s
Aave = 2.5m/s /8s= .3125 m/s^2 when slope is .05
Vave= 10m/ 5 s= 2m/s
Vf= 2m/s *2= 4m/s
AAve= 4m/s /5s= .8m/s^2 when slope is .10
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10 min
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Good, but you still need to calculate the final result.
&#See any notes I might have inserted into your document. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your solutions with the expanded discussion at the link
Solution
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