wk3qz2

course phy201

6/28 9

Determine the acceleration of an object whose velocity is initially 19 cm/s and which accelerates uniformly through a distance of 67 cm in 5.4 seconds.vAve= 67 cm/ 5.4s= 12.41 cm/s

vf= 12.41cm/s*2-19cm/s= 5.82 cm/s

a= -13.18 cm/s / 5.4s= - 2.44 cm/s^2"

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