course Phy 121
9/27/09 around 7:52am
The problem:A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion:
vf = v0 +a*’dt
(12cm/s + 8cm.s^2) *(3s)
12cm/s + 24cm/s = 36cm/s
• Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion:
If is constant it will be the same .
• How far will it travel during this interval?
answer/question/discussion:
‘ds =(12cm/s)*(3s) + (.5)*(8cm/s^2)* (3s^2)
36cm + 36 cm
72cm
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