assignment 8

course mth 158

{wbEJwWx߂[v؝assignment #001

Your work has been received. Please scroll through the document to see any inserted notes (inserted at the appropriate place in the document, in boldface) and a note at the end. The note at the end of the file will confirm that the file has been reviewed; be sure to read that note. If there is no note at the end, notify the instructor through the Submit Work form, and include the date of the posting to your access page.

001. `Query 1

College Algebra

03-04-2008

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assignment #008

008. `query 8

College Algebra

03-04-2008

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21:37:20

**** query R.8.12. Simplify the cube root of 54

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RESPONSE -->

sq rt 9 x 6 = 3 sq rt 2

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21:47:49

**** query R.8.30. Simplify 2 sqrt(12) - 3 sqrt(27).

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RESPONSE -->

2*cube rt 3 x 4 - 3* cube rt 9 x 3 =2x2*cube rt 3 -3 x 3 cube rt 3 =4 cube rt 3 - 9* cube rt 3 = (4-9) cube rt 3+ -5 cube rt 3

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21:53:57

Extra Question: What is the simplified form of (2 sqrt(6) + 3) ( 3 sqrt(6)) and how did you get this result?

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RESPONSE -->

2 x 2 cube rt 3 +3 3 x 2 cube rt 3

4 cube rt 3 6 cube rt 3

7 cube rt 3 6 cube rt 3

(7+6) cube rt 3

13 cube rt 3

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21:54:24

**** query R.8. Expand (sqrt(x) + sqrt(5) )^2

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RESPONSE -->

Enter, as appropriate, an answer to the question, a critique of your answer in response to a given answer, your insights regarding the situation at this point, notes to yourself, or just an OK.

Always critique your solutions by describing any insights you had or errors you makde, and by explaining how you can make use of the insight or how you now know how to avoid certain errors. Also pose for the instructor any question or questions that you have related to the problem or series of problems.

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21:54:24

**** query R.8. Expand (sqrt(x) + sqrt(5) )^2

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RESPONSE -->

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21:54:29

**** query R.8. Expand (sqrt(x) + sqrt(5) )^2

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RESPONSE -->

ok

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22:01:33

**** query R.8.48. Rationalize denominator of sqrt(2) / (sqrt(7) + 2)

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RESPONSE -->

sq rt 2/sq rt 7-2 x sq rt 7 -2/ sq rt 7 - 2

sq rt 7 ( sq rt 7 - 2)/ 4-7

2 sq rt 7 + sq rt 49/ -3

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22:04:02

Extra Question: What steps did you follow to simplify (x^3)^(1/6) and what is your result, assuming that x is positive and expressing your result with only positive exponents?

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RESPONSE -->

i dont understand question

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22:07:24

**** query R.8.60. Simplify 25^(3/2).

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RESPONSE -->

( cube rt 25) ^3

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22:12:06

Extra Question: What is the simplified form of (24)^(1/3) and how did you get this result?

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RESPONSE -->

cube rt 24

6 sq rt 4

6 sq rt 2

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22:12:40

** (x^2y)^(1/3) * (125x^3)^(1/3)/ ( 8 x^3y^4)^(1/3)

(x^(2/3)y^(1/3)* (5x)/[ 8^(1/3) * xy(y^(1/3)]

(x^(2/3)(5x) / ( 2 xy)

5( x^(5/3)) / ( 2 xy)

5x(x^(2/3)) / ( 2 xy)

5 ( x^(2/3) ) / (2 y) **

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RESPONSE -->

ok

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22:16:32

Extra question. What is the simplified form of sqrt( 4 ( x+4)^2 ) and how did you get this result?

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RESPONSE -->

2(x + 4) (x + 4)

2(x^2 +4x +4x+8)

2(x^2 +8x +8)

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22:17:00

Query Add comments on any surprises or insights you experienced as a result of this assignment.

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RESPONSE -->

ok

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assignment #010

010. `query 10

College Algebra

03-04-2008

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22:19:43

query 1.1.20 (was 1.1.12). Explain, step by step, how you solved the equation 5y + 6 = -18 - y

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RESPONSE -->

5y + y = -24 - y +y

6y/6=-24/6

x=-4

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22:20:31

query 1.1.38 \ 44 (was 1.1.30). Explain, step by step, how you solved the equation (2x+1) / 3 + 16 = 3x

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RESPONSE -->

ok

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assignment #010

010. `query 10

College Algebra

03-04-2008

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22:22:40

query 1.1.38 \ 44 (was 1.1.30). Explain, step by step, how you solved the equation (2x+1) / 3 + 16 = 3x

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RESPONSE -->

ok

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22:22:43

** STUDENT SOLUTION:

(2x + 1) / 3 + 16 = 3x

First, multiply both sides of the equation by 3

2x +1 + 48 =9x or 2x + 49 = 9x

subtract 2x from both sides.

49 = 7x

Divide both sides by 7

7 = x

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RESPONSE -->

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22:24:51

query was 1.1.44 \ 36. Explain, step by step, how you solved the equation (x+2)(x-3) = (x+3)^2

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RESPONSE -->

x^2 -3x+2x-6=x^2 -3x +2x -6

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22:25:14

** STUDENT SOLUTION: (x+2)(x+3) = (x+3)^2

First, we use the distributive property to remove the parenthesis and get

x^2 - x - 6 = x^2 + 6x + 9

subtract x^2 from both sides,

-x - 6 = 6x + 9

Subtract 9 from both sides

- x - 6 - 9 = 6x or -x - 15 = 6x

add x to both sides

-15 = 7x

Divide both sides by 7

-15/7 = x

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RESPONSE -->

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Given solutions and self-critiques should be included. Without this information I cannot efficiently process your work in order to quickly see, in your own words, what you do and do not understand.

I note as before that you do not appear to have completed the Step 8 assignments in the Orientation, which give you a first encounter with these programs.

A synopsis for the Query program:

&#To run the program correctly you click on the Next Question/Solution button (top left), enter your response in the Answer box (the box at top right), click on the Enter Response button (above the top right box), then again on the Next Question/Solution botton (top left) to see the solution, and finally enter your response or self-critique in the Answer box and click on Enter Response.

You then start the process over with the next question, clicking on the Next Question/Solution button at top left, etc.

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You should resubmit your work complete with given solutions and self-critiques so I can provide any assistance you might need. You could, for example, copy and paste the solutions you have given here, then having seen the given solutions, you would add self-critiques on those that differ from your solutions.