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PHY 121
Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-
and-forth oscillation (extreme point to equilibrium to opposite extreme point back to
equilibrium and finally to the original extreme point). As long as the amplitude of the
motion (the amplitude is the distance from the equilibrium position to the extreme
point) is small compared to the length of the pendulum, the time required for a cycle is
independent of the amplitude.
How long does it take to get from one extreme point to the other, how long from an
extreme point to equilibrium, and how long to go from extreme point to equilibrium to
opposite extreme point and back to equilibrium?
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It should take 1 second to get from one extreme point to the other because that is half of one full cycle.
To get from extreme point to equilibrium, it would be 1/2 second. To go from extreme point to equilibrium would be another 1/2 second and from opposite extreme point and back to equilibrium another 1/2 second for a total of 1.5 seconds.
What reasonable assumption did you make to arrive at your answers?
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answer/question/discussion: ->->->->->->->->->->->-> :
I assumed that I could split the entire cycle into four equal parts and that the slowing down/momentarily stopping at each end did not need to be factored into the time.
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30 minutes? I didn't pay attention
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&#Your work looks very good. Let me know if you have any questions. &#