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PHY 121
Your 'cq_1_17.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A child in a car tosses a ball upward so that after release it requires 1/2 second to
rise and fall back into the child's hand at the same height from which it was released.
The car is traveling at a constant speed of 10 meters / second in the horizontal
direction.
Between release and catch, how far did the ball travel in the horizontal direction?
answer/question/discussion: ->->->->->->->->->->->-> :
The ball is traveling with the car at 10 m/s. In .5 sec, it will travel 5 meters.
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As observed by a passenger in the car, what was the path of the ball from its release
until the instant it was caught?
answer/question/discussion: ->->->->->->->->->->->-> :
To a passenger in the car, the path of the ball will be straight up and then straight
back down.
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Sketch the path of the ball as observed by a line of people standing along the side of
the road. Describe your sketch. What was shape of the path of the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
From the street, the path of the ball will look like an upside-down u, going backward.
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How fast was the ball moving in the vertical direction at the instant of release? At
that instant, what is its velocity as observed by a line of people standing along the
side of the road?
answer/question/discussion: ->->->->->->->->->->->-> :
-9.8 m/s^2 * .5 s = 4.9 m/s
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If it took 1/2 second to come to rest, this would be correct. However in 1/2 second it rises then falls back to its original position.
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How high did the ball rise above its point of release before it began to fall back down?
answer/question/discussion: ->->->->->->->->->->->-> :
4.9 m/s * .5 s = 2.45 m for the trip. For half a trip, it's 1.225 meters.
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** **
20 min
** **
A child in a car tosses a ball upward so that after release it requires 1/2 second to
rise and fall back into the child's hand at the same height from which it was released.
The car is traveling at a constant speed of 10 meters / second in the horizontal
direction.
Between release and catch, how far did the ball travel in the horizontal direction?
answer/question/discussion: ->->->->->->->->->->->-> :
The ball is traveling with the car at 10 m/s. In .5 sec, it will travel 5 meters.
#$&*
As observed by a passenger in the car, what was the path of the ball from its release
until the instant it was caught?
answer/question/discussion: ->->->->->->->->->->->-> :
To a passenger in the car, the path of the ball will be straight up and then straight
back down.
#$&*
Sketch the path of the ball as observed by a line of people standing along the side of
the road. Describe your sketch. What was shape of the path of the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
From the street, the path of the ball will look like an upside-down u, going backward.
#$&*
How fast was the ball moving in the vertical direction at the instant of release? At
that instant, what is its velocity as observed by a line of people standing along the
side of the road?
answer/question/discussion: ->->->->->->->->->->->-> :
-9.8 m/s^2 * .5 s = 4.9 m/s
#$&*
How high did the ball rise above its point of release before it began to fall back down?
answer/question/discussion: ->->->->->->->->->->->-> :
4.9 m/s * .5 s = 2.45 m for the trip. For half a trip, it's 1.225 meters.
#$&*
*#&!
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Good, but you did misinterpret what happened during that 1/2 second.
See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your old and new solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem.
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