#$&*
PHY 121
Your 'cq_1_19.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
The equilibrant of a force is the force which is equal and opposite to that force. If two forces are equal and opposite, their x and y components are also equal, but the x and y components of the force are opposite in sign to those of the equilibrant.
The x and y components of a force are 2 Newtons and 3 Newtons repectively.
What are the magnitude of this force and what angle does it make as measured counterclockwise from the positive x axis?
magnitude: a^2 + b^2 = c^2
(2 N)^2 + (3N)^2 = c^2
4 N^2 + 9 N^2 = c^2
13 N^2 = c^2
c = 3.6 N
angle: tan-1 (3/2) = 56 degrees
#$&*
What are the components of the equilibrant force?
-2 N and -3 N
#$&*
What angle does the equilibrant force make as measured counterclockwise from the positive x axis?
tan -1 (-3/-2) = 56 degrees
#$&*
@&
The equilibrant is in the direction opposite the force, so it can't have the same angle.
The angle of any vector measured counterclockwise from the positive x axis is
arcTan( y comp / x comp), plus 180 degrees if the x component is negative.
So the angle is 56 deg + 180 deg = 236 deg.
*@
*#&!
Your work looks good. See my notes. Let me know if you have any questions.