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PHY 121
Your 'cq_1_19.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_19.2_labelMessages **
Sketch a vector representing a 10 Newton force which acts vertically downward.
Position an x-y coordinate plane so that the initial point of your vector is at the
origin, and the angle of the vector as measured counterclockwise from the positive x
axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from
its traditional horizontal-vertical orientation.
answer/question/discussion: ->->->->->->->->->->->-> :
I started by making a point and a ray pointing straight down. Then I turned my paper to
make it look traditional, used that as the x axis and drew a perpendicular y axis. From
there I estimated about 250 degrees and drew a new ray.
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What are the x and y components of the equilibrant of the force?
answer/question/discussion: ->->->->->->->->->->->-> :
x = 10 N (cos) (250 deg) = -3.4 N
y = 10 N (sin) (250 deg) = -9.4 N
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This looks very good. Let me know if you have any questions.