cq_1_192

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PHY 121

Your 'cq_1_19.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** CQ_1_19.2_labelMessages **

Sketch a vector representing a 10 Newton force which acts vertically downward.

Position an x-y coordinate plane so that the initial point of your vector is at the

origin, and the angle of the vector as measured counterclockwise from the positive x

axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from

its traditional horizontal-vertical orientation.

answer/question/discussion: ->->->->->->->->->->->-> :

I started by making a point and a ray pointing straight down. Then I turned my paper to

make it look traditional, used that as the x axis and drew a perpendicular y axis. From

there I estimated about 250 degrees and drew a new ray.

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What are the x and y components of the equilibrant of the force?

answer/question/discussion: ->->->->->->->->->->->-> :

x = 10 N (cos) (250 deg) = -3.4 N

y = 10 N (sin) (250 deg) = -9.4 N

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&#This looks very good. Let me know if you have any questions. &#