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PHY 121
Your 'cq_1_21.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball is tossed vertically upward and caught at the position from which it was released.
Ignoring air resistance will the ball at the instant it reaches its original position be traveling faster, slower, or at the same speed as it was when released?
answer/question/discussion: ->->->->->->->->->->->-> :
Because the acceleration is 9.8 m/s^2 from gravity, and because it is released and caught at the same position, it should be going the same speed as when it was released. This is because gravity is pulling on it and slowing it down to the point that it stops momentarily and returns to its original position.
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What, if anything, is different in your answer if air resistance is present? Give your best explanation.
answer/question/discussion: ->->->->->->->->->->->-> :
Air resistance will push against the ball the same amount whether it is going up or coming back down. It will slow it down the same in both directions, so I think that the initial and final velocities will still remain the same.
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10 min
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If the acceleration is the same in both directions the ball will have the same speed on its return.
Is the acceleration the same in both directions?
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