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PHY 121
Your 'cq_1_23.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_23.1_labelMessages **
cq_1_231
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PHY121
Your 'cq_1_23.1' report has been received. Scroll down through the document to see any
comments I might have inserted, and my final comment at the end.
** CQ_1_23.1_labelMessages **
A wad of paper is dropped from a second-story balcony and falls through still air to the
ground.
As it speeds up, what happens to the air resistance it encounters?
answer/question/discussion: ->->->->->->->->->->->-> : ->->->->->->->->->->->-> :
The air pushes back on it more.
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What happens to the net force acting on it?
answer/question/discussion: ->->->->->->->->->->->-> : ->->->->->->->->->->->-> :
The gravity is pulling and the air is pulling. This causes the paper to fall at a
steady speed.
&&&&The gravity pulls at a steady pace. The paper speeds up as it falls. Air resistance increases. However, if the air resistance matched the pull of gravity, then the paper couldn't speed up. Net force is in gravity's favor.&&&&
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If the paper falls long enough, the magnitude of the air resistance will in fact approach the magnitude of the force exerted by gravity, and the net force being the sum of the two opposite forces will approach zero. The velocity at which these forces are equal and opposite is the terminal velocity.
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What happens to its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> : ->->->->->->->->->->->-> :
It remains steady.
&&&&It increases&&&&
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As the paper speeds up the force of air resistance increases, while the force exerted by
gravity remains constant.
So the net force is not constant and the acceleration will not remain the same.
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If it dropped from a much higher point, what would happen to the net force and the
acceleration?
answer/question/discussion: ->->->->->->->->->->->-> : ->->->->->->->->->->->-> :
Gravity would have more opportunities to pull on the paper because of the distance, but
the air would also have more time to push on the paper and try to slow it down. So, I
believe that at a higher point, the net force would remain the same.
&&&&Net force would be + for gravity/downward and - for air resistance/upward.&&&&
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*#&!
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I'll ask you to rethink some of your responses in light of my note.
Don't spend an inordinate amount of time on this, but do give it 10 minutes or so.
&#Please see my notes and submit a copy of this document with revisions, comments and/or
questions, and mark your insertions with &&&& (please mark each insertion at the
beginning and at the end).
Be sure to include the entire document, including my notes.
&#
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5 more minutes
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&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your old and new solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#