course phy 202
First I was trying to find P1. So I had (P1/P0)=(T1/T0). Then I had P1/1atm=300/270(270P1=300atm)/270
P1=1.11atm
pmax=patm[(tmax/to)-1]
10^5 Kpascals in 1 atm.
(1.11atm*10^5 - 10^5)=111000
(1000kg/m^3)(9.8m/s^2)('y)=111000
111000/9800='y
1.1326meters
you've got too many zeros in the 111000.
1.11 atm = 111,000 Pa but
(1.11atm*10^5 - 10^5)=11100 Pa, not 111,000 Pa
(1000kg/m^3)(9.8m/s^2)('y)=11100 Pa
111000 Pa / (9800 N / m^3) =`dy
`dy = 1.1326meters
Use units in all quantities
(1000kg/m^3)(9.8m/s^2)(.2m)=1960Kpascals
At what temperature will that system give me that pressure?
101969/1atm=t2/270=275.92 would equal t2
v2/v1=t2/t1
v2/.5=300/275.292
(275.292v2=150)/275.292=v2=.54487
'pg=mgh
.54487-.5=.04487 volume pushed out
1000kg/m^3=m/v
mass = 44.87
you didn't put any units on your mass
44.87*9.8*.2=87.94 Joules
kg * m/s^2 * m gives you Joules. However you didn't get 44.89 kg into that bottle, much less raise that much water. That would be over 100 lbs of water.
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You did the right procedures. Your made some unit errors and one power-of-10 error. See my notes..