course phy 202

First I was trying to find P1. So I had (P1/P0)=(T1/T0). Then I had P1/1atm=300/270(270P1=300atm)/270

P1=1.11atm

pmax=patm[(tmax/to)-1]

10^5 Kpascals in 1 atm.

(1.11atm*10^5 - 10^5)=111000

(1000kg/m^3)(9.8m/s^2)('y)=111000

111000/9800='y

1.1326meters

you've got too many zeros in the 111000.

1.11 atm = 111,000 Pa but

(1.11atm*10^5 - 10^5)=11100 Pa, not 111,000 Pa
(1000kg/m^3)(9.8m/s^2)('y)=11100 Pa
111000 Pa / (9800 N / m^3) =`dy
`dy = 1.1326meters

Use units in all quantities

(1000kg/m^3)(9.8m/s^2)(.2m)=1960Kpascals

At what temperature will that system give me that pressure?

101969/1atm=t2/270=275.92 would equal t2

v2/v1=t2/t1

v2/.5=300/275.292

(275.292v2=150)/275.292=v2=.54487

'pg=mgh

.54487-.5=.04487 volume pushed out

1000kg/m^3=m/v

mass = 44.87

you didn't put any units on your mass

44.87*9.8*.2=87.94 Joules

kg * m/s^2 * m gives you Joules. However you didn't get 44.89 kg into that bottle, much less raise that much water. That would be over 100 lbs of water.

you've got too many zeros in the 111000. 1.11 atm = 111,000 Pa but (1.11atm*10^5 - 10^5)=11100 Pa, not 111,000 Pa (1000kg/m^3)(9.8m/s^2)('y)=11100 Pa 111000 Pa / (9800 N / m^3) =`dy `dy = 1.1326meters Use units in all quantities

you didn't put any units on your mass

You did the right procedures. Your made some unit errors and one power-of-10 error. See my notes..

you've got too many zeros in the 111000.

1.11 atm = 111,000 Pa but

(1.11atm*10^5 - 10^5)=11100 Pa, not 111,000 Pa
(1000kg/m^3)(9.8m/s^2)('y)=11100 Pa
111000 Pa / (9800 N / m^3) =`dy
`dy = 1.1326meters

Use units in all quantities