course phy 202

First I was trying to find P1. So I had (P1/P0)=(T1/T0). Then I had P1/1atm=300/270(270P1=300atm)/270

P1=1.11atm

pmax=patm[(tmax/to)-1]

10^5 Kpascals in 1 atm.

(1.11atm*10^5 - 10^5)=111000

(1000kg/m^3)(9.8m/s^2)('y)=111000

111000/9800='y

1.1326meters

you've got too many zeros in the 111000.

1.11 atm = 111,000 Pa but

(1.11atm*10^5 - 10^5)=11100 Pa, not 111,000 Pa

(1000kg/m^3)(9.8m/s^2)('y)=11100 Pa

111000 Pa / (9800 N / m^3) =`dy

`dy = 1.1326meters

Use units in all quantities

(1000kg/m^3)(9.8m/s^2)(.2m)=1960Kpascals

At what temperature will that system give me that pressure?

101969/1atm=t2/270=275.92 would equal t2

v2/v1=t2/t1

v2/.5=300/275.292

(275.292v2=150)/275.292=v2=.54487

'pg=mgh

.54487-.5=.04487 volume pushed out

1000kg/m^3=m/v

mass = 44.87

you didn't put any units on your mass

44.87*9.8*.2=87.94 Joules

kg * m/s^2 * m gives you Joules. However you didn't get 44.89 kg into that bottle, much less raise that much water. That would be over 100 lbs of water.

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You did the right procedures. Your made some unit errors and one power-of-10 error. See my notes..