course phy 202
This is a reply to 1/30/07
Here is what I calculated for the data I turned in yesterday. Trial 1 For X axis
I took (1000kg/m3)(9.8m/s2)(.658m)=6448.4N/m2 or pascals.
For the Y axis
(16.2/16.2-1.5)=1.102041
Trial 2
For X axis
(1000kg/m3)(9.8m/s2)(1.103m)=10809.4 pascals
For Y Axis
(16.2/16.2-2.3)=1.165468
Trial 3
For X axis
(1000kg/m3)(9.8m/s2)(.701m)=6869.8 pascals
For Y Axis
(16.2/16.2-1.5)=1.102041
Since there is an x and y I really don't know where to start to calculate what pressure in pascals would equal 1 atm. I know that in normal circumstances 1 atm equals 1.01325*10^2 kpascals. "
You have correctly calculated the pressures in the air column.
This needs to be combined with your results from Bernoulli's Equation in order to get an estimate of atmospheric pressure.