document 2

course phy 202

This is a reply to 1/30/07

Here is what I calculated for the data I turned in yesterday. Trial 1 For X axis

I took (1000kg/m3)(9.8m/s2)(.658m)=6448.4N/m2 or pascals.

For the Y axis

(16.2/16.2-1.5)=1.102041

Trial 2

For X axis

(1000kg/m3)(9.8m/s2)(1.103m)=10809.4 pascals

For Y Axis

(16.2/16.2-2.3)=1.165468

Trial 3

For X axis

(1000kg/m3)(9.8m/s2)(.701m)=6869.8 pascals

For Y Axis

(16.2/16.2-1.5)=1.102041

Since there is an x and y I really don't know where to start to calculate what pressure in pascals would equal 1 atm. I know that in normal circumstances 1 atm equals 1.01325*10^2 kpascals. "

You have correctly calculated the pressures in the air column.

This needs to be combined with your results from Bernoulli's Equation in order to get an estimate of atmospheric pressure.