course Mth 158
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21:16:08 query R.3.12 (was R.3.6) What is the hypotenuse of a right triangle with legs 14 and 48 and how did you get your result?
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RESPONSE --> a = 14, b = 48 c^2 = a^2 + b^2 c^2 = 14^2 + 48^2 = 196 + 2304 = 2500 c = 50
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21:17:03 query R.3.18 (was R.3.12). Is a triangle with legs of 10, 24 and 26 a right triangle, and how did you arrive at your answer?
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RESPONSE --> ok
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21:19:15 ** Using the Pythagorean Theorem we have c^2 = a^2 + b^2, if and only if the triangle is a right triangle. Substituting we get 26^2 = 10^2 + 24^2, or 676 = 100 + 576 so that 676 = 676 This confirms that the Pythagorean Theorem applies and we have a right triangle. **
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RESPONSE --> 10, 24, 26 26^2 = 10^2 + 24^2 676 = 100 + 576 676 = 676 Yes, this is a right triangle, and the length of the hypotenuse is 26
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21:43:30 ** To find the volume and surface are a sphere we use the given formulas: Volume = 4/3 * pi * r^3 V = 4/3 * pi * 3^3 V = 4/3 * pi * 27 V = 36pi m^3 Surface Area = 4 * pi * r^2 S = 4 * pi * 3^2 S = 4 * pi * 9 S = 36pi m^2. **
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RESPONSE --> ok
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21:52:23 query R.3.42 (was R.3.36). A pool of radius 10 ft is enclosed by a deck of width 3 feet. What is the area of the deck and how did you obtain this result?
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RESPONSE --> A=*pi*r^2 A=*pi*10^2 A=*pi*100 A=(3.14)(100) A=314 ft^2 A=*pi*r^2 A=*pi*13^2 A=*pi*169 A=(3.14)(169) A=530.66 ft^2 A=530.66 - 314 =216.66ft^2
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21:53:06 ** The deck plus the pool gives you a circle of radius 10 ft + 3 ft = 13 ft. The area of the deck plus the pool is therefore pi * (13 ft)^2 = 169 pi ft^2. So the area of the deck must be deck area = area of deck and pool - area of pool = 169 pi ft^2 - 100 pi ft^2 = 69 pi ft^2. **
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RESPONSE --> I multiplied out pi, is that okay?
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