Phy 201
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
Situation A
vAve = 10 m / 8 s
vAve = 1.25 m/s
vf = 1.25 m/s
v0 is zero so vf cannot be the same as vAve
aAve = 1.25 m/s / 8 s
aAve = .156 m/s/s
Situation B
vAve = 10 m / 5 s
vAve = 2 m/s
vf = 2 m/s
aAve = 2 m/s / 5 s
aAve = .4 m/s/s
(.156 m/s/s + .4 m/s/s) / 2 = .278 m/s/s
This is the average of your two acceleration values, not the requested rate.
#$&*
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10 minutes
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Solution
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