Orientation VIII Rates

course PHY201

»±ßòöÔV¼ù“ëa|ñâÉ߸ɛi”­assignment #001

Your work has been received. Please scroll through the document to see any inserted notes (inserted at the appropriate place in the document, in boldface) and a note at the end. The note at the end of the file will confirm that the file has been reviewed; be sure to read that note. If there is no note at the end, notify the instructor through the Submit Work form, and include the date of the posting to your access page.

001. Rates

qa rates

08-19-2007

......!!!!!!!!...................................

18:31:42

`q001. You should copy and paste these instructions to a word processor for reference. However you can always view them, as well as everything else that has appeared in this box, by clicking the 'Display Everything' button.

1. For the next question or answer, you click on 'Next Question / Answer' button above the box at top left until a question has been posed. Once a question has been posed you are to answer before you click again on this button.

2. Before clicking for an answer, type your best answer to the current question into the box to the right, then clip on the 'Enter Answer' button.

3. After entering your answer you will click on 'Next Question / Answer' to view the answer to the question. Do not tamper with the information displayed in the left-hand box.

4. If your answer was incorrect, incomplete or would otherwise require revision, you will enter a self-critique. If you learned something from the answer, you need to restate it in your own words in order to reinforce your learning. If there is something you feel you should note for future reference, you should make a note in your own words. Go to the response box (the right-hand box) and type in a self-critique and/or notes, as appropriate. Do not copy and paste anything from the left-hand box, since that information will be saved in any case.

5. If you wish to save your response to your Notes file you may choose to click on the 'Save As Notes' button rather than the 'Enter Answer' button. Doing so will save your work for your future reference. Your work will be saved in a Notes file in the c:\vhmthphy folder. The title of the Notes file will also include the name you gave when you started the program.

6. After clicking either the 'Enter Response' or the 'Save as Notes' button, click on 'Next Question / Answer' and proceed in a similar manner.

In the right-hand box briefly describe your understanding of these instructions, then click 'Enter Answer'.

......!!!!!!!!...................................

RESPONSE -->

I understand.

confidence assessment: 3

.................................................

......!!!!!!!!...................................

18:32:03

Your answer has been noted. Enter 'ok' in the Response Box and click on Enter Response, then click on Next Question/Answer for the first real question.

......!!!!!!!!...................................

RESPONSE -->

okay

confidence assessment: 3

.................................................

......!!!!!!!!...................................

18:33:42

`q002. Note that there are 10 questions in this assignment. The questions are of increasing difficulty--the first questions are fairly easy but later questions are very tricky. The main purposes of these exercises are to refine your thinking about rates, and to see how you process challenging information. Continue as far as you can until you are completely lost. Students who are prepared for the highest-level math courses might not ever get lost.

If you make $50 in 5 hr, then at what rate are you earning money?

......!!!!!!!!...................................

RESPONSE -->

If you make $50 an hour in 5 hours, then you make $10 dollars an hour.

50/5 = 10

confidence assessment: 3

.................................................

......!!!!!!!!...................................

18:34:06

The rate at which you are earning money is the number of dollars per hour you are earning. You are earning money at the rate of 50 dollars / (5 hours) = 10 dollars / hour. It is very likely that you immediately came up with the $10 / hour because almosteveryone is familiar with the concept of the pay rate, the number of dollars per hour. Note carefully that the pay rate is found by dividing the quantity earned by the time required to earn it. Time rates in general are found by dividing an accumulated quantity by the time required to accumulate it.

You need to make note of anything in the given solution that you didn't understand when you solved the problem. If new ideas have been introduced in the solution, you need to note them. If you notice an error in your own thinking then you need to note that. In your own words, explain anything you didn't already understand and save your response as Notes.

......!!!!!!!!...................................

RESPONSE -->

okay

confidence assessment: 3

.................................................

......!!!!!!!!...................................

18:35:45

`q003.If you make $60,000 per year then how much do you make per month?

......!!!!!!!!...................................

RESPONSE -->

With 12 monthes in a year, divide $60K by 12 monthes:

$60K/12 monthes = 5K/month

confidence assessment: 3

.................................................

......!!!!!!!!...................................

18:36:00

Most people will very quickly see that we need to divide $60,000 by 12 months, giving us 60,000 dollars / (12 months) = 5000 dollars / month. Note that again we have found a time rate, dividing the accumulated quantity by the time required to accumulate it.

You need to make note of anything in the given solution that you didn't understand when you solved the problem. If new ideas have been introduced in the solution, you need to note them. If you notice an error in your own thinking then you need to note that. In your own words, explain anything you didn't already understand and save your response as Notes.

......!!!!!!!!...................................

RESPONSE -->

okay

confidence assessment: 3

.................................................

......!!!!!!!!...................................

18:37:46

`q004. Suppose that the $60,000 is made in a year by a small business. Would be more appropriate to say that the business makes $5000 per month, or that the business makes an average of $5000 per month?

......!!!!!!!!...................................

RESPONSE -->

If a business makes $60K a year, it would be more appropriate to say that the business makes an average of $5K a month; because there may some monthes that the business makes more/less money than others.

confidence assessment: 3

.................................................

......!!!!!!!!...................................

18:38:06

Small businesses do not usually make the same amount of money every month. The amount made depends on the demand for the services or commodities provided by the business, and there are often seasonal fluctuations in addition to other market fluctuations. It is almost certain that a small business making $60,000 per year will make more than $5000 in some months and less than $5000 in others. Therefore it is much more appropriate to say that the business makes and average of $5000 per month.

You need to make note of anything in the given solution that you didn't understand when you solved the problem. If new ideas have been introduced in the solution, you need to note them. If you notice an error in your own thinking then you need to note that. In your own words, explain anything you didn't already understand and save your response as Notes.

......!!!!!!!!...................................

RESPONSE -->

okay

confidence assessment: 3

.................................................

......!!!!!!!!...................................

18:40:39

`q005. If you travel 300 miles in 6 hours, at what average rate are you covering distance, and why do we say average rate instead of just plain rate?

......!!!!!!!!...................................

RESPONSE -->

If you cover 300 miles in 6 hours, you should be averaging 50 mph. It should be considered average, because it is most likely that the driver may have to stop for gas, food, or bathroom breaks.

300 miles/6 hours = 50 mph

confidence assessment: 3

.................................................

......!!!!!!!!...................................

18:41:56

The average rate is 50 miles per hour, or 50 miles / hour. This is obtained by dividing the accumulated quantity, the 300 miles, by the time required to accumulate it, obtaining ave rate = 300 miles / ( 6 hours) = 50 miles / hour. Note that the rate at which distance is covered is called speed. The car has an average speed of 50 miles/hour. We say 'average rate' in this case because it is almost certain that slight changes in pressure on the accelerator, traffic conditions and other factors ensure that the speed will sometimes be greater than 50 miles/hour and sometimes less than 50 miles/hour; the 50 miles/hour we obtain from the given information is clearly and overall average of the velocities.

You need to make note of anything in the given solution that you didn't understand when you solved the problem. If new ideas have been introduced in the solution, you need to note them. If you notice an error in your own thinking then you need to note that. In your own words, explain anything you didn't already understand and save your response as Notes.

......!!!!!!!!...................................

RESPONSE -->

I didnt think of varying speed by weather conditions, hills, traffic, etc.

Other than that, I am okay.

confidence assessment: 3

.................................................

......!!!!!!!!...................................

18:45:34

`q006. If you use 60 gallons of gasoline on a 1200 mile trip, then at what average rate are you using gasoline, with respect to miles traveled?

......!!!!!!!!...................................

RESPONSE -->

If you travel 1200 miles and use 60 gallons of fuel, then divide 1200 miles by 60 gallons of fuel to come to the conclusion that you average fuel consumption around 20 mpg.

confidence assessment: 3

.................................................

......!!!!!!!!...................................

18:49:00

The rate of change of one quantity with respect to another is the change in the first quantity, divided by the change in the second. As in previous examples, we found the rate at which money was made with respect to time by dividing the amount of money made by the time required to make it.

By analogy, the rate at which we use fuel with respect to miles traveled is the change in the amount of fuel divided by the number of miles traveled. In this case we use 60 gallons of fuel in 1200 miles, so the average rate it 60 gal / (1200 miles) = .05 gallons / mile.

Note that this question didn't ask for miles per gallon. Miles per gallon is an appropriate and common calculation, but it measures the rate at which miles are covered with respect to the amount of fuel used. Be sure you see the difference.

Note that in this problem we again have here an example of a rate, but unlike previous instances this rate is not calculated with respect to time. This rate is calculated with respect to the amount of fuel used. We divide the accumulated quantity, in this case miles, by the amount of fuel required to cover those miles. Note that again we call the result of this problem an average rate because there are always at least subtle differences in driving conditions that require the use of more fuel on some miles than on others.

It's very important to understand the phrase 'with respect to'. Whether the calculation makes sense or not, it is defined by the order of the terms.

In this case gallons / mile tells you how many gallons you are burning, on the average, per mile. This concept is not as familiar as miles / gallon, but except for familiarity it's technically no more difficult.

You need to make note of anything in the given solution that you didn't understand when you solved the problem. If new ideas have been introduced in the solution, you need to note them. If you notice an error in your own thinking then you need to note that. In your own words, explain anything you didn't already understand and save your response as Notes.

......!!!!!!!!...................................

RESPONSE -->

I guess I did it the opposite way. Maybe I read the question wrong. My answer is correct with an avg of 20 mpg. So take the reciprocal of that to get .05 gallons/ mile.

confidence assessment: 3

Most students give this answer, and the situation does correspond to 20 mpg.

However, as you'll be seeing, it's important to do rate problems in the appropriate order, and the question here asked for rate of use with respect to miles traveled.

.................................................

......!!!!!!!!...................................

18:51:06

`q007. The word 'average' generally connotes something like adding two quantities and dividing by 2, or adding several quantities and dividing by the number of quantities we added. Why is it that we are calculating average rates but we aren't adding anything?

......!!!!!!!!...................................

RESPONSE -->

The reason that we are calculating average rates without adding anything is because we are relying the common knowledge that there are other variables that could come into pay for these equations, yet there is no mention of them or about them being constant.

confidence assessment: 3

.................................................

......!!!!!!!!...................................

18:52:12

The word 'average' in the context of the dollars / month, miles / gallon types of questions we have been answering was used because we expect that in different months different amounts were earned, or that over different parts of the trip the gas mileage might have varied, but that if we knew all the individual quantities (e.g., the dollars earned each month, the number of gallons used with each mile) and averaged them in the usual manner, we would get the .05 gallons / mile, or the $5000 / month. In a sense we have already added up all the dollars earned in each month, or the miles traveled on each gallon, and we have obtained the total $60,000 or 1200 miles. Thus when we divide by the number of months or the number of gallons, we are in fact calculating an average rate.

You need to make note of anything in the given solution that you didn't understand when you solved the problem. If new ideas have been introduced in the solution, you need to note them. If you notice an error in your own thinking then you need to note that. In your own words, explain anything you didn't already understand and save your response as Notes.

......!!!!!!!!...................................

RESPONSE -->

I am good

confidence assessment: 3

.................................................

......!!!!!!!!...................................

19:05:02

`q008. In a study of how lifting strength is influenced by various ways of training, a study group was divided into 2 subgroups of equally matched individuals. The first group did 10 pushups per day for a year and the second group did 50 pushups per day for year. At the end of the year to lifting strength of the first group averaged 147 pounds, while that of the second group averaged 162 pounds. At what average rate did lifting strength increase per daily pushup?

......!!!!!!!!...................................

RESPONSE -->

With Team A completeing 10 push-ups a day for 365 days, we understand that Team A completed 3,650 push-ups in a year. Then at the end of the year Team A averaged 147 lbs in the lift competition. So by dividing 147 lbs. by 3,650 push-ups, we discover that during every push-up the team averaged a strength gain of 0.0403 lbs. per push-up.

With Team B completeing 50 push-ups a day for 365 days, we understand that Team B completed 18,250 push-ups in a year. Then at the end of the year Team A averaged 162 lbs in the lift competition. So by dividing 162 lbs. by 18,250 push-ups, we discover that during every push-up the team averaged a strength gain of 0.0089 lbs. per push-up.

Team A gained more strength per push-up.

confidence assessment: 3

.................................................

......!!!!!!!!...................................

19:08:51

The second group had 15 pounds more lifting strength as a result of doing 40 more daily pushups than the first. The desired rate is therefore 15 pounds / 40 pushups = .375 pounds / pushup.

You need to make note of anything in the given solution that you didn't understand when you solved the problem. If new ideas have been introduced in the solution, you need to note them. If you notice an error in your own thinking then you need to note that. In your own words, explain anything you didn't already understand and save your response as Notes.

......!!!!!!!!...................................

RESPONSE -->

I was under the presumption that we were going on total strength gained per push-up with the gains being made after a years worth of work.

I was wrong. I got it now though.

confidence assessment: 3

.................................................

......!!!!!!!!...................................

19:15:56

`q009. In another part of the study, participants all did 30 pushups per day, but one group did pushups with a 10-pound weight on their shoulders while the other used a 30-pound weight. At the end of the study, the first group had an average lifting strength of 171 pounds, while the second had an average lifting strength of 188 pounds. At what average rate did lifting strength increase with respect to the added shoulder weight?

......!!!!!!!!...................................

RESPONSE -->

With two groups: A & B, one using a 30 lb weight and the other using a 10 lb. weight, the difference of the two would be 20 lbs. The average strength of team A was 171 lbs., while team B averaged 188 lbs. The difference of those two was 17. By dividing 17 by 20, we conclude that an average strength gain was acheived at a rate of 0.85 lbs. per added pound of weight.

confidence assessment: 3

.................................................

......!!!!!!!!...................................

19:16:08

The difference in lifting strength was 17 pounds, as a result of a 20 pound difference in added weight. The average rate at which strength increases with respect added weight would therefore be 17 lifting pounds / (20 added pounds) = .85 lifting pounds / added pound. The strength advantage was .85 lifting pounds per pound of added weight, on the average.

You need to make note of anything in the given solution that you didn't understand when you solved the problem. If new ideas have been introduced in the solution, you need to note them. If you notice an error in your own thinking then you need to note that. In your own words, explain anything you didn't already understand and save your response as Notes.

......!!!!!!!!...................................

RESPONSE -->

i am good

yup

confidence assessment: 3

.................................................

......!!!!!!!!...................................

19:26:13

`q010. During a race, a runner passes the 100-meter mark 12 seconds after the start and the 200-meter mark 22 seconds after the start. At what average rate was the runner covering distance between those two positions?

......!!!!!!!!...................................

RESPONSE -->

With the given information, from the start it took the runner 12 sec to cover the first 100 m, and 22 sec to make it to the 200 m mark. This means that the second 100 m was covered in 10 seconds ( 22 - 12 = 10). Therefore, the runner covered an average speed between the 100 m and 200 m marks (200m - 100m = 100m) at 10 meters/sec (100/10 = 10). Or you could say that the runner covered an average time of 0.10 sec/meter (10/100 = 0.1)

confidence assessment: 3

.................................................

......!!!!!!!!...................................

19:26:29

The runner traveled 100 meters between the two positions, and required 10 seconds to do so. The average rate at which the runner was covering distance was therefore 100 meters / (10 seconds) = 10 meters / second. Again this is an average rate; at different positions in his stride the runner would clearly be traveling at slightly different speeds.

You need to make note of anything in the given solution that you didn't understand when you solved the problem. If new ideas have been introduced in the solution, you need to note them. If you notice an error in your own thinking then you need to note that. In your own words, explain anything you didn't already understand and save your response as Notes.

......!!!!!!!!...................................

RESPONSE -->

okay

confidence assessment: 3

.................................................

......!!!!!!!!...................................

19:40:04

`q011. During a race, a runner passes the 100-meter mark moving at 10 meters / second, and the 200-meter mark moving at 9 meters / second. What is your best estimate of how long it takes the runner to cover the 100 meter distance?

......!!!!!!!!...................................

RESPONSE -->

If the runner covered 200 m total: the first 100 m at a rate of 10 m/sec and the second 100 m at a rate of 9 m/sec; then we could conclude that the runner ran at an average speed of 10.55 m/sec ( (10+9) / 2 = 10.55 ). Next we would divide the 100 m distance between the two points by the average speed, 10.55 m/sec to find the result that it should take the runner about 9.524 sec to run from the 100m mark to the 200 m mark.

confidence assessment: 3

.................................................

......!!!!!!!!...................................

19:41:36

At 10 meters/sec, the runner would require 10 seconds to travel 100 meters. However the runner seems to be slowing, and will therefore require more than 10 seconds to travel the 100 meters. We don't know what the runner's average speed is, we only know that it goes from 10 m/s to 9 m/s. The simplest estimate we could make would be that the average speed is the average of 10 m/s and 9 m/s, or (10 m/s + 9 m/s ) / 2 = 9.5 m/s. Taking this approximation as the average rate, the time required to travel 100 meters will be (100 meters) / (9.5 m/s) = 10.5 sec, approx.. Note that simply averaging the 10 m/s and the 9 m/s might not be the best way to approximate the average rate--for example we if we knew enough about the situation we might expect that this runner would maintain the 10 m/s for most of the remaining 100 meters, and simply tire during the last few seconds. However we were not given this information, and we don't add extraneous assumptions without good cause. So the approximation we used here is pretty close to the best we can do with the given information.

You need to make note of anything in the given solution that you didn't understand when you solved the problem. If new ideas have been introduced in the solution, you need to note them. If you notice an error in your own thinking then you need to note that. In your own words, explain anything you didn't already understand and save your response as Notes.

......!!!!!!!!...................................

RESPONSE -->

Yeah, I screwed up the math. I think plugged in my answers backward. I have it though.

confidence assessment: 3

.................................................

......!!!!!!!!...................................

19:43:16

`q012. We just averaged two quantities, adding them in dividing by 2, to find an average rate. We didn't do that before. Why we do it now?

......!!!!!!!!...................................

RESPONSE -->

Because the problems we were look at did not require that type of logic to find the answer.

confidence assessment: 2

.................................................

......!!!!!!!!...................................

19:43:54

In previous examples the quantities weren't rates. We were given the amount of change of some accumulating quantity, and the change in time or in some other quantity on which the first was dependent (e.g., dollars and months, miles and gallons). Here we are given 2 rates, 10 m/s and 9 m/s, in a situation where we need an average rate in order to answer a question. Within this context, averaging the 2 rates was an appropriate tactic.

You need to make note of anything in the given solution that you didn't understand when you solved the problem. If new ideas have been introduced in the solution, you need to note them. If you notice an error in your own thinking then you need to note that. In your own words, explain anything you didn't already understand and save your response as Notes.

......!!!!!!!!...................................

RESPONSE -->

Because we were working with rates.

confidence assessment: 3

.................................................

......!!!!!!!!...................................

19:44:07

end program

......!!!!!!!!...................................

RESPONSE -->

confidence assessment: 3

.................................................

You're doing fine here. Good detail on solutions and self-critiques.