Assignment 17

course Mth 272

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Your work has been received. Please scroll through the document to see any inserted notes (inserted at the appropriate place in the document, in boldface) and a note at the end. The note at the end of the file will confirm that the file has been reviewed; be sure to read that note. If there is no note at the end, notify the instructor through the Submit Work form, and include the date of the posting to your access page.

16:53:44

Query problem 6.3.18 integrate 3/(x ^ 2 - 3x)

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RESPONSE -->

confidence assessment:

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16:53:48

What is your integral?

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RESPONSE -->

-ln(x) + ln(x-3) + C

confidence assessment: 2

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16:54:01

Explain how you used partial fractions to obtain your result.

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RESPONSE -->

x^2-3x = x(x-3)

3/(x(x-3)) = A/x + B/(x-3)

when x = 3, B = 1

When x = 0, A = -1

int 3/x^2-3x dx = int -1/x + 1/(x-3)

= -ln(x) + ln(x-3) + C

confidence assessment: 2

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16:54:12

Query problem 6.3.29 (was 6.3.27) integrate (x+2) / (x^2 - 4x)

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RESPONSE -->

-1/2 ln(x) + 3/2 ln(x-4) + c

confidence assessment: 2

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16:54:22

What is your integral?

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RESPONSE -->

-1/2 ln(x) + 3/2 ln(x-4) + c

confidence assessment: 2

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16:54:33

Explain how you used partial fractions to obtain your result.

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RESPONSE -->

x^2 - 4x = x(x-4)

x+2/(x^2-4x) = a/x + b/(x-4)

x+2 = a(x-4) + b(x)

when x = 4, B = 3/2

when x = 0, A = -1/2

int x+2/(x^2-4x) dx = int -1/2(1/x) + 3/2(1/(x-4)

= -1/2 ln(x) + 3/2 ln(x-4) + c

confidence assessment: 2

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16:54:35

Query Add comments on any surprises or insights you experienced as a result of this assignment.

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RESPONSE -->

confidence assessment:

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Very good work. Let me know if you have questions. &#