course PHY 231

7/6 23:47

Over a period of 10 seconds, an object increases its velocity at a uniform rate from 3 m/s to 27 m/s

What is its acceleration and how far does it travel?

Graph velocity vs. clock time for this object and explain what the slope of the

graph means and why, and also what the area means and why.

'dt = 10sec

v_i = 3m/sec

v_f = 27m/sec

'dV = 27m/sec - 3m/sec = 24m/sec

A = 'dv/'dt = (24m/sec) / 10sec = 2.4m/sec^2

Acceleration is the slope of a uniformly accelerated 'dv vs 'dt graph. The slope

will be a constant 2.4units of rise/run.

The area underneath the graph is the average velocity of the object during the

time interval."