PHY 231
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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
v0 = 0
'ds = -2m
'dt = 0.64s
v_avg = -2m/0.64s = -3.125m/s = -3.1m/s
vf = -6.2m/s
'dv = -6.2m/s
a = -6.2m/0.64s^2 = -9.6875m/s^2 = -9.7m/s^2
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Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
'ds = -5m
v0 = 0
'dt = 1.05s
v_avg = -5m/1.05s = -4.76m/s = -4.8m/s
vf = -9.6/s
'dv = -9.6/s
a = -9.6m/1.05s^2 = -9.14m/s^2 = -9.1m/s^2
It is similar
#$&*
Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
Almost. But not completely.
#$&*
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5 minutes
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&#This looks very good. Let me know if you have any questions. &#