course PHY 231
7/14 0105
A projectile leaves the edge of a table and, while traveling horizontally at a constant velocity, falls freely a distance of 125 cm to the floor. It travels a horizontal distance of
11.1 cm during its fall. If its vertical acceleration is 980 cm/s2, how long does it take to
fall and what is its horizontal velocity during the fall?
'dsy = -125cm
'dsx = 11.1cm
ay = -980cm/s^2
v0y = 0cm/s
'dsy = v0y'dt + 0.5*ay*'dt^2
-125cm = -490cm'dt^2/s^2
0.255s^2 (cm/cm) = 'dt^2
'dt = 0.51s
vfx = v0x = 2vavgx = 2*'dsx/'dt = 43.5cm/s
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