phy201
Your 'cq_1_07.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Seed 7.1
A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
'ds= 2meters
v0= 0
'dt= .64seconds
'ds= (v0 + vf )/2 * 'dt
vf= 2 'ds - v0 /'dt
vf= (2 * 2m) - 0 m/s / .64s
vf= 4m - 0 m/s / .64s
vf= 6.25 m/s
a= 'dv / 'dt
a= 6.25 m/s- 0m/s / .64s
a= 9.77 m/s^2
#$&*
Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
'ds = 5m
'dt = 1.05s
'ds = vave * 'dt
'ds= 3.125m/s * 1.05s
'ds= 3.28m
It's not clear where you got 3.125 m/s.
no this is not consistant uing the final velocity of 6.25m/s starting out initially at 0 in the time given of 1.05 seconds.
#$&*
Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
Yes, the ball when dropped from 2 meters had an acceleration rate of 9.8 m/s^2. This is consistent since the ball is free falling.
#$&*
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about 30 minutes
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Your first acceleration is good; not sure how you got the second but the method you used for the first would have worked.
Please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.