phy201
Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
Seed 7.2
An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
'ds = 10 meters
slope = .05
'dt 8 seconds
v0 = 0 m/s
vf= 20m - 0m/s/8s
Vf= 2.5m/s
a= 'dv/'dt
a= (2.5m/s- 0m/s) / 8s
a=.31m/s^2
'dt = 5s
'ds= 10 m
slope = .10
v0= 0
Vf= 20m - 0m/s /5s
Vf= 4m/s
a= 'dv / 'dt
a= 4m/s /5s
a= .8m/s^2
Acceleration is changing .8m/s^2-.31m/s^2= .49m/s^2
rate changing or slope .10-.05 = .05
acceleration changes with respect to slope
.49/.05 =9.8m/s^2
So this seems consistent with if the slope has increased, then the acceleration increases with the acceleration of gravity
** **
about 30 min
** **
Very well done. No revision is necessary, but you might want to compare your work to the discussion at the link, just to clarify a little of the terminology.
&#Please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified. &#