phy201
Your 'cq_1_19.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Seed question 19.1
The equilibrant of a force is the force which is equal and opposite to that force. If two forces are equal and opposite, their x and y
components are also equal, but the x and y components of the force are opposite in sign to those of the equilibrant.
The x and y components of a force are 2 Newtons and 3 Newtons repectively.
What are the magnitude of this force and what angle does it make as measured counterclockwise from the positive x axis?
magnitude = sqrt ((2n) ^2 + (3n) ^2)
magnitude = sqrt (4n^2 + 9n^2)
magnitude = 3.61N
tan-1(3N/2N) = 56.31
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What are the components of the equilibrant force?
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What angle does the equilibrant force make as measured counterclockwise from the positive x axis?
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I am not sure how to work this one
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I am having a really hard time witht these types of problem, I understand that x=cos(theta) and Y= sin(theta), but I am confused on the rest. I think the magnitude is found by sqrt(x^2+y^2)
I'm sure you'll understand this when you read the discussion at the link provided below. However, if you don't, be sure to ask.
Please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.