phy201
Your 'cq_1_19.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Seed question 19.1
The equilibrant of a force is the force which is equal and opposite to that force. If two forces are equal and opposite, their x and y
components are also equal, but the x and y components of the force are opposite in sign to those of the equilibrant.
The x and y components of a force are 2 Newtons and 3 Newtons repectively.
What are the magnitude of this force and what angle does it make as measured counterclockwise from the positive x axis?
magnitude = sqrt ((2n) ^2 + (3n) ^2)
magnitude = sqrt (4n^2 + 9n^2)
magnitude = 3.61N
tan-1(3N/2N) = 56.31
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What are the components of the equilibrant force?
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What angle does the equilibrant force make as measured counterclockwise from the positive x axis?
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I am not sure how to work this one
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I am having a really hard time witht these types of problem, I understand that x=cos(theta) and Y= sin(theta), but I am confused on the rest. I think the magnitude is found by sqrt(x^2+y^2)
I'm sure you'll understand this when you read the discussion at the link provided below. However, if you don't, be sure to ask.
&#Please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified. &#