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Phy 121
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_11.1_labelMessages **
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Answer the following based on Newton's Second Law:
• How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
Net force is mass times acceleration or 12kg * 3m/s^2 = 36kg*m/s^2 (Newton)
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• What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> :
The acceleration is the net force divided by the mass or 20 N (kg*m/s^2) / 4 kg = 5m/s^2
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• If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> :
A 20 newton force on a 10 kg object should accelerate the object at 2m/s^2 based on what we know. If the acceleration was only 1.5m/s^2, there is some other force acting on the system, maybe friction, meaning that some of the 20 newton force is lost in the presence of other forces.
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• What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> :
The 20 newton force minus a hypothetical friction of 5 newtons would result in a net force on the system of 15 Newtons, which if divided by our 10kg object would result in an acceleration of 1.5m/s^2
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&#Very good responses. Let me know if you have questions. &#