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PHY 121
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
The net force is 9.8 Newtons. The acceleration is .89 m/s^2 . You can do this by multiplying 5 and 6 kg * 9.8 m/s^2. So you can subtract the 5kg mass by the 6 kg. Which is 9.8 Newtons. So you can divide 9.8 by the total mass which was 11 kg to get the acceleration.
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If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
I think it would be 3.6 m/s as the final speed after 1 second. The direction would still be going down.
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During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
The velocity and acceleration would be in the same direction. The system would be slowing down though because there is a 6kg object on the other side of the pulley.
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&#Very good responses. Let me know if you have questions. &#
@& Note, however, that if acceleration and velocity are in the same direction then the object speeds up. In this case acceleration and velocity are in opposite directions, *@