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Phy 231
Your 'cq_1_19.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The equilibrant of a force is the force which is equal and opposite to that force. If two forces are equal and opposite, their x and y
components are also equal, but the x and y components of the force are opposite in sign to those of the equilibrant.
The x and y components of a force are 2 Newtons and 3 Newtons repectively.
What are the magnitude of this force and what angle does it make as measured counterclockwise from the positive x axis?
Magnitude= sqrt[(2N)^2+(3N)^2]
=sqrt(13N^2)
=3.6N
Theta=arctan(3/2)
=56.3deg counterclockwise from the positive x-axis
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What are the components of the equilibrant force?
The equilibriant force would have an x-component of -2N and a y-component of -3N, for a magnitude of 3.6N
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What angle does the equilibrant force make as measured counterclockwise from the positive x axis?
The angle would be 180 degrees beyond the original angle: 236.3deg counterclockwise from the positive x-axis
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&#Very good responses. Let me know if you have questions. &#