cq_1_242

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Phy 231

Your 'cq_1_24.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** CQ_1_24.2_labelMessages **

A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows to 50

cm / sec and the marble speeds up to 70 cm / sec.

Is the total momentum of the system after collision the same as the total momentum before?

answer/question/discussion: ->->->->->->->->->->->-> scussion:

Initial momentum = (60g*80cm/s)+0

=4800g*cm/s

Final momentum = (60g*50m/s)+(20g*70cm/s)

=3000g*cm/s+1400g*cm/s

=4400g*cm/s

No, final momentum is less than initial momentum of the system.

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What would the marble velocity have to be in order to exactly conserve momentum, assuming the steel ball's velocities to be accurate?

answer/question/discussion: ->->->->->->->->->->->-> scussion:

Since the steel ball's final momentum is 3000g*cm/s, the marble's final momentum would need to be 1800g*cm/s in order to perfectly conserve momentum.

1800g*cm/s=20g*v

v=90cm/s

The marble would need to have a velocity of 90cm/s.

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5 minutes

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&#Very good responses. Let me know if you have questions. &#