Phy 231
Your 'cq_1_03.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball starts with velocity 0 and accelerates uniformly down a ramp of length 30 cm, covering the distance in 5 seconds.
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What is its average velocity?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
(30 cm - 0 cm)/(5 seconds - 0 seconds) = 6 cm/s is the average velocity
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If the acceleration of the ball is uniform then its average velocity is equal to the average of its initial and final velocities.
You know its average velocity, and you know the initial velocity is zero.
What therefore must be the final velocity?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
Since vInit and vAve are, respectively, 0 cm/s and 6 cm/s, and
(vInit + vFinal)/2 = vAve, then
(0 + vFinal)/2 = 6 cm/s
vFinal = 12 cm/s
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By how much did its velocity therefore change?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
Since 12 cm/s - 0 cm/s is 12 cm/s, it changed 12 cm/sec
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At what average rate did its velocity change with respect to clock time?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
Since the interval was 5 sec, and the change in velocity was 12 cm/sec, then
(12 cm/sec)/5 sec = 2.4 cm/s^2
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What would a graph of its velocity vs. clock time look like? Give the best description you can.
answer/question/discussion: ->->->->->->->->->->->-> scussion:
It would be a linear line (acceleration uniform) increasing at an increasing rate.
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10-12 minutes
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&#This looks very good. Let me know if you have any questions. &#