Phy 231
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Answer the following based on Newton's Second Law:
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How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
Fnet = m * a
Fnet = (12 kg) * (3 m/s^2) = 36 (kg * m)/s^2 = 36 N
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What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
Fnet = m * a
20 N = 4 kg * a
5 N/kg = a
5 (kg * m/s^2)/kg = 5 m/s^2 = a
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If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
Fnet = m * a
20 N = 10kg * 1.5 m/s^2
20 N = 15 N is not true, so
Fnet = 20 N - 5 N, so you know that extra 5 N is operating against your direction
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What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
Since Fnet = m * a,
Fnet = 10 kg * 1.5 m/s^2, and
Fnet = 15 N, and it would be in the direction of your exerted force
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10 min
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&#This looks very good. Let me know if you have any questions. &#