Liberal Arts Mathematics

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course Mth 151

2/11 2

Question: `q001. Consider the statement 'If that group of six-year-olds doesn't have adult supervision, they won't act in an orderly manner.' Under which of the following circumstances would everyone have to agree that the statement is false? The group does have supervision and they do act in an orderly manner.

The group doesn't have supervision and they don't act in an orderly manner.

The group doesn't have supervision and they do act in an orderly manner.

The group does have supervision and they don't act in an orderly manner.

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Your solution:

If the group doesn’t have supervision and they do act in an orderly manner it would make the previous statement that they wouldn’t act in an orderly manner false.

confidence rating #$&*:5

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Given Solution:

`aThe statement says that if the group doesn't have supervision, they will not act in an orderly manner. So if they don't have supervision and yet do act in an orderly manner the statement is contradicted.

If the group does have supervision, the statement cannot be contradicted because condition of the statement, that the group doesn't have supervision, does not hold. The statement has nothing to say about what happens if the group does have supervision.

Of course if the group doesn't have supervision and doesn't act in orderly manner this is completely consistent with the statement.

Therefore the only way to statement can be considered false is the group doesn't have supervision and does act in an overly manner.

Note that what we know, or think we know, about childrens' behavior has nothing at all to do with the logic of the situation. We could analyze the logic of a statement like 'If the Moon is made of green cheese then most six-year-olds prefer collard greens to chocolate ice cream'. Anything we know about the composition of the Moon or the tastes of children has nothing to do with the fact that the only way this statement could be shown false would be for the Moon to be made of green cheese and most six-year-olds to prefer the ice cream.

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Question: `q002. List the different orders in which the letters a, b and c could be arranged (examples are 'acb' and 'cba'). Explain how you know that your list contains every possible order.

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Your solution:

I arrange the possibilities in alphabetical order and exhaust the letters to make sure the list contains every possible answer. The possible arangments of the letters a, b, and c are abc, acb, bac, bca, cab, cba

confidence rating #$&*: 5

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Given Solution:

`aThe only reliable way to get all possible orders is to have a system which we are sure the list every order without missing any.

Perhaps the simplest way to construct all possible orders is to list then alphabetically.

We start with abc. There is only one other order that starts with a, and it is obtained by switching the last two letters to get acb.

The next alphabetical order must start with b. The first possible listing starting with b must follow b with a, leaving c for last. The orders therefore bac. The only other order starting with b is bca.

The next order must start with c, which will be followed by a to give us cab. The next order is obtained by switching the last two letters to get cba.

This exhausts all possibilities for combinations of the three letters a, b and c. Our combinations are, in alphabetical order,

abc, acb, bac, bca, cab, cba.

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Question: `q003. One collection consists of the letters a, c, d and f. Another collection consists of the letters a, b, d and g.

List the letters common to both collections.

List the letters which appear in at least one of the collections.

List the letters in the first half of the alphabet which do not appear in either of the collections.

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Your solution:

The two letters that appear in both collections and therefor is common in the collections is a and d.

The letters that appeared in at least one collection is a, b, c, d, f, and g.

The letters in the first half of the alphabet that did not appear in either collection is e, h, I, j, k, l, and m. Since the first half of the alphabet ends at m.

confidence rating #$&*: 5

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Given Solution:

`aTo letters a and d each appear in both collections. No other letter does.

The letters a, c, d, and f appear in the first collection, so they all in at least one of the collections. In addition to letters b and g appear in the second collection. Therefore letters a, b, c, d, f and g all appear in at least one of the collections.

We consider the letters in the first half of the alphabet, in alphabetical order. a, b, c and d all appear in at least one of the collections, but the letter e does not. The letters f and g also appear in at least one of the collections, but none of the other letters of the alphabet do. The first half of the alphabet ends at m, so the list of letters in the first half of the alphabet which do not occur in at least one of the collections is e, h, i, j, k, l, m.

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Question: `q004. Give the next element in each of the following patterns and explain how you obtained each:

2, 3, 5, 8, 12, ...

3, 6, 12, 24, ...

1, 3, 4, 7, 11, 18, ...

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Your solution:

The next number would be 17 this is known because of the pattern seen by the other number is the series which show each number being subtracted by the place it is in. The last number would be in the fifth place and is subtracted by 5 to get 12 which was the number before it.

The next number for this sequence would be 48 because each number is being doubled, since the last number listed was 24 when it got doubled it became 48.

The pattern for this series is simply adding the two numbers that came before the one listed. Since the two numbers before the sequence stopped was 11 and 18 when added together is shows the next number is 29.

confidence rating #$&*: 5

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Given Solution:

`aThe pattern of the sequence 2, 3, 5, 8, 12, ... can be seen by subtracting each number from its successor. 3-2 = 1, 5-3 = 2, 8-5 = 3, 12-8 = 4. The sequence of differences is therefore 1, 2, 3, 4, ... . The next difference will be 5, indicating that the next number must be 12 + 5 = 17.

The pattern of the sequence 3, 6, 12, 24, ... can be discovered by dividing each number into its successor. We obtain 6/3 = 2, 12/6 = 2, 24/12 = 2. This shows us that we are doubling each number to get the next. It follows that the next number in the sequence will be the double of 24, or 48.

The pattern of the sequence 1, 3, 4, 7, 11, 18, ... is a little obvious. Starting with the third number in the sequence, each number is the sum of the two numbers proceeding. That is, 1 + 3 = 4, 3 + 4 = 7, 4 + 7 = 11, and 7 + 11 = 18. It follows that the next member should be 11 + 18 = 29.

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Question: `q005. The number 18 can be 'broken down' into the product 9 * 2, which can then be broken down into the product 3 * 3 * 2, which cannot be broken down any further . Alternatively 18 could be broken down into 6 * 3, which can then be broken down into 2 * 3 * 3.

Show how the numbers 28 and 34 can be broken down until they can't be broken down any further.

Show that there at least two different ways to break down 28, but that when the breakdown is complete both ways end up giving you the same numbers.

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Your solution:

28 can be broken down by 14*2 which can continue to be broken down into 2*2*7 which is the final answer and can’t be broken down further.

34 is an even number and therefor can be divided by 2 to give us 2*17 as the breakdown. Since neither 2 nor 17 can be broken down further 2*17 is the final answer.

confidence rating #$&*: 5

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Given Solution:

`aA good system is to begin by attempting to divide the smallest possible number into the given number. In the case of 34 we see that the number can be divided by 2 give 34 = 2 * 17. It is clear that the factor 2 cannot be further broken down, and is easy to see that 17 cannot be further broken down. So the complete breakdown of 34 is 2 * 17.

To breakdown 28 we can again divide by 2 to get 28 = 2 * 14. The number 2 cannot be further broken down, but 14 can be divided by 2 to give 14 = 2 * 7, which cannot be further broken down. Thus we have 28 = 2 * 2 * 7.

The number 28 could also the broken down initially into 4 * 7. The 4 can be further broken down into 2 * 2, so again we get 28 = 2 * 2 * 7.

It turns out that the breakdown of a given number always ends up with exactly same numbers, no matter what the initial breakdown.

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Question: `q006. Give the average of the numbers in the following list: 3, 4, 6, 6, 7, 7, 9. By how much does each number differ from the average?

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Your solution:

To find the average of the numbers you must first add all of the number to find the answer 42 which you divide by the amount of numbers you added, 7. The average is 6. 3 is 3 less than the average, 4 is 2 shy of the average, 7 is 1 more than the average, and 9 is 3 more than the average.

confidence rating #$&*: 5

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Given Solution:

`aTo average least 7 numbers we add them in divide by 7. We get a total of 3 + 4 + 6 + 6 + 7 + 7 + 9 = 42, which we then divide by 7 to get the average 42 / 7 = 6.

We see that 3 differs from the average of 6 by 3, 4 differs from the average of 6 by 2, 6 differs from the average of 6 by 0, 7 differs from the average of 6 by 1, and 9 differs from the average of 6 by 3.

A common error is to write the entire sequence of calculations on one line, as 3 + 4 + 6 + 6 + 7 + 7 + 9 = 42 / 7 = 6. This is a really terrible habit. The = sign indicates equality, and if one thing is equal to another, and this other today third thing, then the first thing must be equal to the third thing. This would mean that 3 + 4 + 6 + 6 + 7 + 7 + 9 would have to be equal to 6. This is clearly not the case. It is a serious error to use the = sign for anything but equality, and it should certainly not be used to indicate a sequence of calculations.

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Question: `q007. Which of the following list of numbers is more spread out, 7, 8, 10, 10, 11, 13 or 894, 897, 902, 908, 910, 912? On what basis did you justify your answer?

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Your solution:

The range of the first list of numbers is 6 which is less of a difference compared to the second list which has a range of 18.

confidence rating #$&*: 5

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Given Solution:

`aThe first set of numbers ranges from 7 to 13, a difference of only 6. The second set ranges from 894 to 912, a difference of 18. So it appears pretty clear that the second set has more variation the first.

We might also look at the spacing between numbers, which in the first set is 1, 2, 0, 1, 2 and in the second set is 3, 5, 6, 2, 2. The spacing in the second set is clearly greater than the spacing in the first.

There are other more sophisticated measures of the spread of a distribution of numbers, which you may encounter in your course.

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Question: `q008. 12 is 9 more than 3 and also 4 times 3. We therefore say that 12 differs from 3 by 9, and that the ratio of 12 to 3 is 4.

What is the ratio of 36 to 4 and by how much does 36 differ from 4?

If 288 is in the same ratio to a certain number as 36 is to 4, what is that number?

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Your solution:

The ratio of 36 to 4 equals 9 and 36 - 4 = 32.

Since the ratio of 36 : 4 = 9 the same ratio of 9 for 288 = 32 so the answer is 288 : 32 = 9

confidence rating #$&*: 5

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Given Solution:

`aJust as the ratio of 12 to 3 is 12 / 3 = 4, the ratio of 36 to 4 is 36 / 4 = 9. 36 differs from 4 by 36 - 4 = 32.

Since the ratio of 36 to 4 is 9, the number 288 will be in the same ratio to a number which is 1/9 as great, or 288 / 9 = 32.

Putting this another way, the question asks for a 'certain number', and 288 is in the same ratio to that number as 36 to 4. 36 is 9 times as great as 4, so 288 is 9 times as great as the desired number. The desired number is therefore 288/9 = 32.

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Question: `q009. A triangle has sides 3, 4 and 5. Another triangle has the identical shape of the first but is larger. Its shorter sides are 12 and 16. What is the length of its longest side?

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Your solution:

The larger triangle appears to be four times larger than the smaller triangle with the measurements of 3, 4, and 5. So with if the side of 3 equals 12 and the other side of 4 equals 16 it’s safe to assume the side of 5 would measure to be 20.

confidence rating #$&*: 5

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Given Solution:

`a** You need to first see that that each side of the larger triangle is 4 times the length of the corresponding side of the smaller. This can be seen in many ways, one of the most reliable is to check out the short-side ratios, which are 12/3 = 4 and 16/4 = 4. Since we have a 4-to-1 ratio for each set of corresponding sides, the side of the larger triangle that corresponds to the side of length 5 is 4 * 5 = 20. **

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Question: `q010. List the different orders in which John, Mary and Sally can be lined up, from left to right, for a picture.

In how many orders can the three be lined up so that the two women are next to each other?

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Your solution:

You can have John, Mary and Sally or John, Sally and Mary or Mary, John and Sarah or Mary, Sarah and John or Sarah, John and Mary, or Sarah, Mary and John. There’s six options all together but only four of them have the two women next to each other.

confidence rating #$&*: 5

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Question: `q011. If John is next to Mary, Sally will be jealous. Sally is jealous. Does it logically follow that John is next to Mary? Explain.

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Your solution:

Yes if Sally gets jealous when John is next to Mary and if Sally is currently jealous it would logically lead to believing John is currently standing next to Mary.

@&

There could well be other reasons for Sally's jealousy. You cannot draw from the given information any conclusion, one way or the other, about why Sally is jealous.

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confidence rating #$&*: 5

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Question: `q012. By how much does each of the numbers 81, 85, 89, 83, 86, 86 differ from the average of the six numbers? The average is a whole number, and you should be able to figure out the number without using a calculator.

Explain how you got your solution.

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Your solution:

The average of the six numbers is 85. 81 is 4 less than the average of 85, 83 is less by 2, 85 is the average, 86 is 1 too high, and 89 is greater than the average by 4.

confidence rating #$&*: 5

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Question: `q013. You have blocks colored red, yellow, blue, orange and pink. I have blocks colored yellow, green, blue, purple, brown and white.

How many colors do you have?

How many colors do I have?

How many colors are there all together?

How many colors do we have in common?

How many colors do I have that you don't?

How many colors do you have that I don't?

If I had 9 colors and you had 12, and if there were a total of 18 colors present, then how many colors would I have that you don't, how many would you have that I don't, and how many would we have in common?

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Your solution:

I have 5 colors, you have 6, and altogether we have 9 colors. There is 2 colors we have in common yellow and blue. You have 4 colors I don’t have and I have 3 colors you don’t have. You would have 7 colors I don’t have and I’d have 10 colors that you wouldn’t have. We would have at least two colors in common.

confidence rating #$&*: 5

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Question: `q014. The number 18 can be 'broken down' into the product 9 * 2, which can then be broken down into the product 3 * 3 * 2, which cannot be broken down any further . Alternatively 18 could be broken down into 6 * 3, which can then be broken down into 2 * 3 * 3.

In how many different ways could we completely break down the number 72?

If we put the numbers in the final breakdown in order from least to greatest, do all possible breakdowns lead to the same result, or is there more than one possible final result?

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Your solution:

72 completely broken down would be 2 * 2 * 2 * 3 * 3 which cannot be broken down any further. There is only one possible final result no matter what you break it down by it’ll lead to the same result.

confidence rating #$&*: 5

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Question: `q015. Of the numbers 1240, 1270, 1320 and 1500, which do you think differs the most from the average of the four numbers? Answer as best you can without doing any calculations, and give your reasoning.

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Your solution:

I think 1500 would differ the most from the average because the other numbers seem fairly close whereas 1500 is not that close to them.

confidence rating #$&*: 4

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Self-critique Rating:

&#Your work looks good. See my notes. Let me know if you have any questions. &#