Ball Drop

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course Phy 201

Ball DropYou dropped a ball from a measured and/or estimated height and estimated the time required for it to drop.

Insert a copy of your data here, along with any previously submitted work you wish to include:

5ft/rest in .5s

Ds: 5ft

Dt: .5s

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What do you think was the percent uncertainty in the measurement of height?

.05 5% .05/5ft= + or - .01 ft

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What do you think was the percent uncertainty in the measurement of the time of fall?

10%, .1/.5 = + or - .2 seconds

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What were the average velocity and, assuming acceleration to have been uniform, the acceleration of the falling ball?

V_ave: 5ft/.5s= 10ft/s

A= 29ft/s/.5s= 4ft/s^2

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Do you mean 20 ft / s / (.5 s)? That would be 40 ft / s^2, not 4 ft / s^2.

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Based on your uncertainty estimates for time of fall and height, what is the percent uncertainty in the acceleration as you observed it?

15%= .15

.15/40ft/s= .00375ft/s

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The uncertainty would be 15% of 40 ft / s^2, which means .15 * 40 ft / s^2 = 6 ft / s^2.

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I think you're OK here, except for an apparent typo or two. Check my notes, though, because you also made a couple of mistakes you'll want to avoid on tests.

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