course esubmit)
Your work has been received. Please scroll to the end of the document to see any inserted notes (in boldface) and a note at the end. The note at the end of the file will confirm that the file has been reviewed; be sure to read that note. If there is no note at the end, notify the instructor through the Submit Work form, and include the date of the posting to your access page.
Problem
Do the following:
Make up a problem for situation # 3, and solve it using direct reasoning.
Accompany your solution with an explanation of the meaning of each step and with a flow diagram.
Then solve the same problem using the equations of uniformly accelerated motion.
Make up a problem for situation # 8, and solve it using the equations of uniformly accelerated motion.
Given v0, vf, and 'ds find 'dt and a using direct reasoning and a flow chart. Then solve the problem using the four equations of uniformly accelerated motion.
The flow chart will look like this. On the top layer there is v0 vf and 'ds. From v0 and vf you can find the change in velocity. There are two lines that link the v0 and vf to 'dv. From the 'dv and 'ds two lines connect them to 'dt. From 'dv and 'dt you can find a, linked by two lines.
Direct reasoning: find change in velocity from initial velocity and final velocity. Using change in velocity and displacement find the change in time. From the change in time and change in velocity find the acceleration.
Use equations of motion:
Use the equation vf^2 = v0^2 + 2 a 'ds to find a
(vf^2 - v0^2) = 2 a 'ds
(vf^2 - v0^2) / (2'ds) = a
use vf = v0 + a 'dt to find 'dt
(vf - v0) = a'dt
(vf - v0) / a = 'dt
For the second part:
Given vf, a , and 'ds find v0 and 'dt using the four equations of uniformly accelerated motion.
Use vf^2 = v0^2 + 2 a 'ds to find v0
vf^2 - 2 a 'ds = vo^2
sqrt(vf^2 - 2 a'ds) = sqrt(vo^2)
sqrt(vf^2 - 2 a 'ds) = vo
Use vf = vo + a'dt to find 'dt
vf - v0 = a'dt
(vf - v0) / a = 'dt
"
This time everything looks very good. It's clear that you understand this well.
Let me know if you have questions.