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course Phy 241
1/9 11
Truck overtakes car
You used a combination of three tracks to simulate the problem in which a car passes before I pull out in my truck.
Insert a copy of your data here, along with any previously submitted work you wish to include:
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Steel Ball overtaking other
Here we had two steel balls. both large. there were two ramps side by side, both with the same slope. ball 1 i'm going to call the ball which was released from rest 20 cm up its ramp.
ball 2 i'm going to call the ball from rest with an extended distance of 10cm up the other ramp (30cm total). both were released from rest.
ball 1 had a ramp slope of 16.6%
ball 2 had ramp slope of about 30%
We made 7 trial runs to see when ball 2 overtook ball 1, how long it took to do it, and at what distance measured down from the initial starting point of ball 2's ramp.
Trial | distance overtook | time
1 21.2cm 1.75s
2 22.5cm 3s
3 25cm 1.7s
4 23.1cm 2.25s
5 23.5cm 2.35s
6 22cm 2.5s
7 23cm 2.55s
I know that the 3s time is pretty much way off, and the 1.7 could be as well, but we could discart that and take the average time it took to overtake, and the average distance it took to overtake it, and grind out some
information from that. I made a graph of velocity vs time as well as distance vs time. both are pretty intersting because the graphs of the two balls overlap at a certain point, and that point is where it overtook the other, and
at what distance it overtook it at.
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Explain how you positioned the ball representing the truck, the ball representing the car, and how you timed the release of each.
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The car was not accelerating, so we positioned two ramps continuously until the ball would roll down the first one accelerating, then hit the second one and almost have 0 acceleration, just like your real world situation.
The second ramp, adjacent to the dual ramp, was set up to have a velocity just greater than the velocity of ramp 1 where it had a near constant velocity, and was released when ball 1 had reached 10cm down the ramp.
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According to your data what was the velocity of the ball representing the car at the instant it passed the position of the ball representing the truck?
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18.18 cm/s
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According to your data what was the acceleration of the ball representing the truck?
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7.9cm/s^2
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According to your observations, what were the positions of the two balls when their velocities matched?
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The ball with no acceleration was approx 12cm down its second ramp of 30cm length. and the ball which was accelerating was 18 down its first and only ramp of 30cm
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According to your previously calculated accelerations and velocities, what were the positions of the two balls when their velocities matched?
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20cm down ramp
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You need to show how you got this, based on your previously calculated velocities and accelerations.
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According to your observations, at what position did the ball representing the truck overtake the ball representing the car?
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22.9cm down ramp
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According to your previously calculated velocities and accelerations, at what position should the ball representing the truck overtake the ball representing the car?
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21cm
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You need to show how you got thisas well, based on your previously calculated velocities and accelerations.
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