course phy202 1.In your own words explain the meaning of the electric field.-The field measures the magnitute and direction of the force of the charge. 2. charges 6 microC on diagonal corners, -6 microC on other diagonal corners of 1 m square; force on each. What is the magnitude and direction of the force on the positive charge at the lower left-hand corner? - We have to use coulombs law in order to find the attractive forces: F = 9 * 10^9 N m^2/C^2 * ( 6 * 10^-6 C) * ( 6 * 10^-6 C) / ( 1 m)^2 = 324 * 10^-3 N = .324 N. The forces for the different directions are: To right=.324N Up=.162 N Down=45 Left=225 These have x,y components: Fy=.162 N sin(225 deg) = -.115 N total force= -.115 N + .324 N = .21 N Fx = .162 N cos(225 deg) = -.115 N total force= -.115 N + .324 N = .21 N Net force= sqrt21 N)^2 + (.21 N)^2) = .29 N with an angle of of tan^-1( .21 N / .21 N) = tan^-1(1) = 45 deg