course phys202
1.Explain whether, and if so how, the force on a charged particle due to the field between two capacitor plates is affected by its velocity.- the force on a charged particle due to the field between the two capacitor plates is not affected by its velocity because the plates do not create a magnetic field.
There is a force due to the electric field between the plates, but the effect of an electric field does not depend on velocity.
2. Explain whether, and if so how, the force on a charged particle due to the magnetic field created by a wire coil is affected by its velocity.
- this is different than the previous question because a wire coil does create a magnetic field perpendicular to the plane of the coil. This depends on the direction of force, if it is perpendicular to the coil then the force is F=qvB
3. Explain how the net force changes with velocity as a charged particle passes through the field between two capacitor plates, moving perpendicular to the constant electric field, in the presence of a constant magnetic field oriented perpendicular to both the velocity of the particle and the field of the capacitor.
- This depends if the velocity is high or low. If it is high the magnetic force is greater in magnitute than the electrostatic force, but if it is higher then the magnetic force is smaller in magnitude than the electrostatic force F=qE
4. Force on wire of length 160 meters carrying 150 amps at 65 degrees to Earth's magnetic field of 5.5 * 10^-5 T.
- we would use the equation is I * L * B sin(theta)
- = 150 amps * 160 meters * 5.5 * 10^-5 T * sin(65 deg) = 1.20 amp * m * (N / (amp m) ) = 1.20 Newtons
5. Force on electron at 8.75 * 10^5 m/s east in vertical upward magnetic field of .75 T.
- the magnitude of the force on a moving charge that is perpindicular is q v B, q being the charge, v is the velocity and B is the field
- F = q v B = 1.6 * 10^-19 C * 8.75 * 10^5 m/s * .75 T = 1.05 * 10^-13 C m/s * T = 1.05 * 10^-13 N.
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